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For a critical angle of 60 degree and the refractive index of the first medium is 1.732, the refractive index of the second medium is
  • a)
    1
  • b)
    1.5
  • c)
    2
  • d)
    1.66
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For a critical angle of 60 degree and the refractive index of the firs...
Answer: b
Explanation: From the definition of Snell law, sin θc = n2/n1. To get n2, put n1 = 1.732 and θc = 60. Thus we get sin 60 = n2/1.732 and n2 = 1.5.
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Most Upvoted Answer
For a critical angle of 60 degree and the refractive index of the firs...
Explanation:

When light travels from one medium to another, its speed and direction change due to the change in refractive index. The critical angle is the angle of incidence at which the angle of refraction is 90 degrees.

Given:
Critical angle = 60 degrees
Refractive index of the first medium = 1.732

Formula:
The relationship between the critical angle and refractive indices of two media is given by Snell's law:

n1 sin(critical angle) = n2 sin(90 degrees)

Calculation:
Given that the critical angle is 60 degrees and the refractive index of the first medium is 1.732, we can substitute these values into Snell's law:

1.732 sin(60 degrees) = n2 sin(90 degrees)

Using the trigonometric identity sin(90 degrees) = 1, the equation simplifies to:

1.732 sin(60 degrees) = n2

Using the value of sin(60 degrees) = sqrt(3)/2, the equation further simplifies to:

1.732 * (sqrt(3)/2) = n2

n2 = 1.5

Therefore, the refractive index of the second medium is 1.5, which corresponds to option B.
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For a critical angle of 60 degree and the refractive index of the first medium is 1.732, the refractive index of the second medium isa)1b)1.5c)2d)1.66Correct answer is option 'B'. Can you explain this answer?
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