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The angle of incidence of a wave of a wave with angle of transmission 45 degree and the refractive indices of the two media given by 2 and 1.3 is
  • a)
    41.68
  • b)
    61.86
  • c)
    12.23
  • d)
    27.89
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The angle of incidence of a wave of a wave with angle of transmission ...
Answer: a
Explanation: The Snell law is given by N1 sin θi = N2 sin θt. To get θi, put N1 = 2, N2 = 1.3, θt = 45 degree. Thus we get θi = sin-1(1.3 sin 45)/2 = 41.68 degree.
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Most Upvoted Answer
The angle of incidence of a wave of a wave with angle of transmission ...
Solution:

Given, angle of transmission = 45 degrees, refractive index of first medium = 2 and refractive index of second medium = 1.3.

Let us assume the angle of incidence as θi.

Using Snell's law of refraction, we have:

n1*sin(θi) = n2*sin(θt)

where n1 and n2 are the refractive indices of the first and second medium respectively, θt is the angle of transmission.

Substituting the given values, we get:

2*sin(θi) = 1.3*sin(45)

sin(θi) = 0.65*sin(45) / 2

sin(θi) = 0.2309

θi = sin^-1(0.2309)

θi = 13.32 degrees

Therefore, the angle of incidence is 13.32 degrees, which is closest to option A (41.68 degrees).
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The angle of incidence of a wave of a wave with angle of transmission 45 degree and the refractive indices of the two media given by 2 and 1.3 isa)41.68b)61.86c)12.23d)27.89Correct answer is option 'A'. Can you explain this answer?
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