Rs. 9800 are invested partly in 9% stock at 75 and 10% stock at 80 to ...
Let the investment in 9% stock be Rs.x Then,investment in 10% stock = Rs.(9800−x)
9/75 × x = 10/80 × (9800−x)
⇒ 3x/25 = (9800−x)/8
⇒24x = 9800 × 25 − 25x
⇒ 49x = 9800×25
⇒x = 5000
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Rs. 9800 are invested partly in 9% stock at 75 and 10% stock at 80 to ...
Investment in 9% stock at 75 and 10% stock at 80 to have equal amounts of incomes.
To solve this problem, we can use the concept of weighted average.
Let's assume that the investment in the 9% stock at 75 is x rupees. Then, the investment in the 10% stock at 80 would be (9800 - x) rupees.
The income from the 9% stock at 75 is given by (x * 9/100) and the income from the 10% stock at 80 is given by ((9800 - x) * 10/100).
According to the problem, the incomes from both stocks should be equal. So, we can set up the following equation:
(x * 9/100) = ((9800 - x) * 10/100)
Simplifying this equation, we get:
9x = (9800 - x) * 10
9x = 98000 - 10x
Adding 10x to both sides and rearranging the equation, we get:
19x = 98000
Dividing both sides by 19, we find:
x = 98000/19
x ≈ 5157.89
So, the investment in the 9% stock at 75 is approximately 5157.89 rupees.