Two Vans start from a place with a speed of 50 kmph at an interval of ...
50*12/60 = 10/60 * (50+x)
600 = 500 + 10x
x = 10 kmph
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Two Vans start from a place with a speed of 50 kmph at an interval of ...
Distance between the vans =50*(12/60)= 10km;
let the speed of car = X km/hr;
opposite direction so, relative speed =(50+X) km/hr;
A/Q car meets two vans at interval of 10 mins ; so distance covered in 10 mins = distance between vans.
so, 10= (50+X)*10/60; solving we get, Speed of car(X)=10km/hr. op(B)
Two Vans start from a place with a speed of 50 kmph at an interval of ...
Approach:
To solve this problem, we can consider the scenario as a relative motion problem. We will calculate the relative speed of the vans and the car, and then use the concept of time taken to cover a certain distance to find the speed of the car.
Calculating Relative Speed:
- The vans start at an interval of 12 minutes, which means the second van starts 12 minutes after the first van.
- The relative speed of the vans = 50 kmph + 50 kmph = 100 kmph
- This is because both vans are moving in the same direction, so their speeds add up.
Calculating Speed of Car:
- The car meets the vans at an interval of 10 minutes.
- This means the car covers the distance between the vans in 10 minutes.
- Let the speed of the car be x kmph.
- Relative speed of car and vans = Speed of car + Speed of vans = x + 100 kmph
- Distance covered by the car in 10 minutes = Relative speed * Time = (x + 100) * 10
- Distance covered by the vans in 12 minutes = 100 * 12
Solving for x:
- Since the distances covered by the car and vans are the same when they meet, we can equate the two distances:
(x + 100) * 10 = 100 * 12
- Simplifying the equation, we get:
10x + 1000 = 1200
10x = 200
x = 20 kmph
Therefore, the speed of the car coming from the opposite direction towards the place is 20 kmph, which is not listed in the options provided. Hence, the correct answer is None of these.