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In the measurement of power on balanced load by two Wattmeter method in a 3-phase circuit, the readings of the Wattmeters are 3 kW and 1 kW respectively, the latter being obtained after reversing the connections to the current coil. The power factor of the load is
- a)0.277
- b)0.554
- c)0.625
- d)0.866
Correct answer is option 'A'. Can you explain this answer?
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In the measurement of power on balanced load by two Wattmeter method i...
(a)
When p.f. < 0.5 one of the wattmeter reads negative power; which is read after reversing the connections to the current coil or pressure coil. Also by formula:
When p.f. < 0.5 one of the wattmeter reads negative power; which is read after reversing the connections to the current coil or pressure coil. Also by formula:
Most Upvoted Answer
In the measurement of power on balanced load by two Wattmeter method i...
The power factor of a load in a three-phase circuit can be determined using the two Wattmeter method. In this method, two Wattmeters are connected in the circuit to measure the power consumed by the load. By analyzing the readings obtained from the Wattmeters, the power factor of the load can be calculated.
Given that the readings of the Wattmeters are 3 kW and 1 kW respectively, and the latter reading is obtained after reversing the connections to the current coil, we can proceed with the calculation of the power factor.
Let's break down the solution into steps:
1. Identify the formula for power factor: The power factor (PF) is defined as the ratio of the real power (P) to the apparent power (S) in a circuit. Mathematically, PF = P / S.
2. Calculate the apparent power: The apparent power can be calculated using the formula S = √(P1^2 + P2^2), where P1 and P2 are the readings obtained from the two Wattmeters.
S = √(3^2 + 1^2)
= √(9 + 1)
= √10
3. Calculate the real power: The real power is the sum of the readings obtained from the Wattmeters.
P = P1 + P2
= 3 + 1
= 4
4. Calculate the power factor: Now, we can calculate the power factor using the formula PF = P / S.
PF = 4 / √10
5. Simplify the power factor: To simplify the power factor, we can rationalize the denominator.
PF = (4 / √10) * (√10 / √10)
= (4√10) / 10
= √10 / 2
6. Approximate the power factor: We can approximate the power factor to the nearest decimal.
PF ≈ 0.316
The closest option to the calculated power factor is option 'A' with a power factor of 0.277.
Therefore, the correct answer is option 'A' (0.277).
Given that the readings of the Wattmeters are 3 kW and 1 kW respectively, and the latter reading is obtained after reversing the connections to the current coil, we can proceed with the calculation of the power factor.
Let's break down the solution into steps:
1. Identify the formula for power factor: The power factor (PF) is defined as the ratio of the real power (P) to the apparent power (S) in a circuit. Mathematically, PF = P / S.
2. Calculate the apparent power: The apparent power can be calculated using the formula S = √(P1^2 + P2^2), where P1 and P2 are the readings obtained from the two Wattmeters.
S = √(3^2 + 1^2)
= √(9 + 1)
= √10
3. Calculate the real power: The real power is the sum of the readings obtained from the Wattmeters.
P = P1 + P2
= 3 + 1
= 4
4. Calculate the power factor: Now, we can calculate the power factor using the formula PF = P / S.
PF = 4 / √10
5. Simplify the power factor: To simplify the power factor, we can rationalize the denominator.
PF = (4 / √10) * (√10 / √10)
= (4√10) / 10
= √10 / 2
6. Approximate the power factor: We can approximate the power factor to the nearest decimal.
PF ≈ 0.316
The closest option to the calculated power factor is option 'A' with a power factor of 0.277.
Therefore, the correct answer is option 'A' (0.277).
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In the measurement of power on balanced load by two Wattmeter method in a 3-phase circuit, the readings of the Wattmeters are 3 kW and 1 kW respectively, the latter being obtained after reversing the connections to the current coil. The power factor of the load isa)0.277b)0.554c)0.625d)0.866Correct answer is option 'A'. Can you explain this answer?
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