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Find the Lorentz force due to a conductor of length 2m carrying a current of 1.5A and magnetic flux density of 12 units.
- a)24
- b)36
- c)32
- d)45
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Find the Lorentz force due to a conductor of length 2m carrying a curr...
Answer: b
Explanation: The Lorentz is given by the product of the current, differential length and the magnetic flux density. Put B = 12, I = 1.5 and L = 2, thus we get F = BIL = 12 x 1.5 x 2 = 36 units.
Explanation: The Lorentz is given by the product of the current, differential length and the magnetic flux density. Put B = 12, I = 1.5 and L = 2, thus we get F = BIL = 12 x 1.5 x 2 = 36 units.
Most Upvoted Answer
Find the Lorentz force due to a conductor of length 2m carrying a curr...
To find the Lorentz force due to a conductor carrying a current in a magnetic field, we can use the formula:
F = I * L * B * sin(theta)
Where:
F is the Lorentz force
I is the current
L is the length of the conductor
B is the magnetic flux density
theta is the angle between the current and the magnetic field
Given:
Length of the conductor (L) = 2m
Current (I) = 1.5A
Magnetic flux density (B) = 12 units
To find the Lorentz force, we need to determine the angle (theta) between the current and the magnetic field.
Since the angle is not given in the question, we assume that the conductor is perpendicular to the magnetic field. In this case, the angle between the current and the magnetic field is 90 degrees.
Now, we can substitute the given values into the formula:
F = 1.5A * 2m * 12 units * sin(90 degrees)
The sin(90 degrees) is equal to 1, so the equation simplifies to:
F = 1.5A * 2m * 12 units * 1
F = 36 units
Therefore, the Lorentz force due to the conductor is 36 units.
Hence, option 'B' is the correct answer.
F = I * L * B * sin(theta)
Where:
F is the Lorentz force
I is the current
L is the length of the conductor
B is the magnetic flux density
theta is the angle between the current and the magnetic field
Given:
Length of the conductor (L) = 2m
Current (I) = 1.5A
Magnetic flux density (B) = 12 units
To find the Lorentz force, we need to determine the angle (theta) between the current and the magnetic field.
Since the angle is not given in the question, we assume that the conductor is perpendicular to the magnetic field. In this case, the angle between the current and the magnetic field is 90 degrees.
Now, we can substitute the given values into the formula:
F = 1.5A * 2m * 12 units * sin(90 degrees)
The sin(90 degrees) is equal to 1, so the equation simplifies to:
F = 1.5A * 2m * 12 units * 1
F = 36 units
Therefore, the Lorentz force due to the conductor is 36 units.
Hence, option 'B' is the correct answer.
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Find the Lorentz force due to a conductor of length 2m carrying a current of 1.5A and magnetic flux density of 12 units.a)24b)36c)32d)45Correct answer is option 'B'. Can you explain this answer?
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