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A two digit number is obtained by both multiplying sum of digit by 8 and adding 1 or by multiplying the difference of the digits by 13 and adding 2. the number is?
Most Upvoted Answer
A two digit number is obtained by both multiplying sum of digit by 8 a...
Let tens digit =x
& once digit = y
.... xy
.. 10x + y


ATQ..
10x+y = 8(x+y)+1
10x +y= 8x +8y +1
2x -7y -1=0 ••••••••••••••••(i)

10x+y = 13(x-y)+2
10x+y = 13x -13y +2
3x -14y +2= 0 •••••••••••••••••••(ii)

solve kr lo aa gayega..
Community Answer
A two digit number is obtained by both multiplying sum of digit by 8 a...
Explanation:

Given Information:
- The two-digit number is obtained by both:
- Multiplying the sum of the digits by 8 and adding 1
- Multiplying the difference of the digits by 13 and adding 2

Let the two-digit number be represented by ab, where 'a' is the tens digit and 'b' is the units digit.

Equations:
1. 8(a + b) + 1 = 10a + b (Multiplying sum of digits by 8 and adding 1)
2. 13(a - b) + 2 = 10a + b (Multiplying difference of digits by 13 and adding 2)

Solving the Equations:
1. Expanding equation 1:
8a + 8b + 1 = 10a + b
8b - b = 10a - 8a - 1
7b = 2a - 1
b = (2a - 1) / 7
2. Substituting b from equation 1 into equation 2:
13(a - ((2a - 1) / 7)) + 2 = 10a + ((2a - 1) / 7)
Simplifying the equation, we get:
a = 4, b = 7
The two-digit number is 47.

Conclusion:
Therefore, the two-digit number that satisfies the given conditions is 47.
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A two digit number is obtained by both multiplying sum of digit by 8 and adding 1 or by multiplying the difference of the digits by 13 and adding 2. the number is?
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