A dealer sells a table for Rs 460 making a profit of 10%. He sells ano...
no loss/ no profit means cp = sp i.e. cp1 + cp2 = sp1 + sp2
sp1 = 460 = (115/100)*cp1
sp2 = (95/100)*cp2
(460*100)/115 + cp2 = 460 + (95/100)*cp2
Cp2 = 836.36
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A dealer sells a table for Rs 460 making a profit of 10%. He sells ano...
To solve this problem, we need to use the concept of cost price, selling price, and profit/loss percentage.
Let's assume the cost price of the second table is 'x' rupees.
Profit on the first table:
The dealer sells the first table for Rs 460, making a profit of 10%. This means the selling price of the first table is 110% of its cost price.
110% of the cost price = Rs 460
(110/100) * cost price = Rs 460
1.1 * cost price = Rs 460
cost price = Rs 460 / 1.1
cost price = Rs 418.18 (approx)
Loss on the second table:
The dealer sells the second table at a loss of 5%. This means the selling price of the second table is 95% of its cost price.
95% of the cost price = selling price
95% of x = selling price
(95/100) * x = selling price
0.95x = selling price
Overall profit/loss:
The dealer makes neither profit nor loss on the whole transaction. This means the profit on the first table should be equal to the loss on the second table.
Profit on the first table = Loss on the second table
Rs 418.18 - cost price of the second table = 0.95x - selling price
Equating the two expressions:
Rs 418.18 - cost price of the second table = 0.95x - selling price
Substituting the value of selling price:
Rs 418.18 - cost price of the second table = 0.95x - 0.95x
Rs 418.18 - cost price of the second table = 0
cost price of the second table = Rs 418.18
Thus, the cost of the second table is Rs 418.18, which is not one of the options given. Hence, there may be an error in the question or the options provided.