A farmer sold a goat and a cow for rupees 800 and got a profit of 20% ...
let cost price of goat = a and cost price of cow = b
800 = (120/100)*a + (125/100)*b
820 = (125/100)*a + (120/100)*b
Solve both equation to get a and b
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A farmer sold a goat and a cow for rupees 800 and got a profit of 20% ...
Let's assume the cost price of the goat is G and the cost price of the cow is C.
Profit on the goat:
The farmer sells the goat and makes a profit of 20%. So, the selling price of the goat is 1.2G.
Profit on the cow:
The farmer sells the cow and makes a profit of 25%. So, the selling price of the cow is 1.25C.
Given that the farmer sold the goat and the cow for a total of rupees 800, we can write the following equation:
1.2G + 1.25C = 800 ...(1)
Now, let's consider the second scenario where the farmer sells the goat and the cow for rupees 820.
Profit on the goat:
The farmer sells the goat and makes a profit of 25%. So, the selling price of the goat is 1.25G.
Profit on the cow:
The farmer sells the cow and makes a profit of 20%. So, the selling price of the cow is 1.2C.
Given that the farmer sold the goat and the cow for a total of rupees 820, we can write the following equation:
1.25G + 1.2C = 820 ...(2)
Now, we have a system of equations with two variables (G and C). We can solve this system to find the cost price of the cow (C).
Solving the system of equations:
To solve the system of equations, we can use any method like substitution or elimination. Let's use the elimination method here.
Multiplying equation (1) by 1.25 and equation (2) by 1.2, we get:
1.5G + 1.5625C = 1000 ...(3)
1.5G + 1.44C = 984 ...(4)
Now, subtracting equation (4) from equation (3), we get:
1.5625C - 1.44C = 1000 - 984
0.1225C = 16
C = 16 / 0.1225
C ≈ 130.612
Therefore, the cost price of the cow is approximately 130.612 rupees, which is closest to option (B) 130.6 rupees.