NEET Exam  >  NEET Questions  >  The velocity of a car moving on a straight ro... Start Learning for Free
The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)
  • a)
    Increases
  • b)
    Decreases
  • c)
    Stay constant
  • d)
    Becomes zero 
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The velocity of a car moving on a straight road increases linearly acc...
View all questions of this test
Most Upvoted Answer
The velocity of a car moving on a straight road increases linearly acc...
Is the initial velocity and b is the acceleration.

To find the displacement of the car as a function of time, we need to integrate the velocity function with respect to time.

v = a bx

dx/dt = v

dx = v dt

Integrating both sides:

∫dx = ∫v dt

x = ∫(a bx) dt

x = a ∫(bx) dt

x = a (1/2 bxt^2 + C)

where C is the constant of integration.

To find C, we need to use the initial condition that x = 0 when t = 0.

x = a (1/2 bxt^2 + C)

0 = a (1/2 bx(0)^2 + C)

0 = aC

C = 0

So the displacement of the car as a function of time is:

x = 1/2 bxt^2 + a

Note that this is a quadratic function of time, which makes sense since the velocity is increasing linearly.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer?
Question Description
The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The velocity of a car moving on a straight road increases linearly according to equation, v = a + bx, where a & b are positive constants. The acceleration in the course of such motion: (x is the displacement)a)Increasesb)Decreasesc)Stay constantd)Becomes zeroCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev