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The Laplacian of the magnetic vector potential will be
- a)–μ J
- b)– μ I
- c)–μ B
- d)–μ H
Correct answer is option 'A'. Can you explain this answer?
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The Laplacian of the magnetic vector potential will bea)–μ Jb...
Answer: a
Explanation: The Laplacian of the magnetic vector potential is given by Del2(A) = -μ J, where μ is the permeability and J is the current density.
Explanation: The Laplacian of the magnetic vector potential is given by Del2(A) = -μ J, where μ is the permeability and J is the current density.
Most Upvoted Answer
The Laplacian of the magnetic vector potential will bea)–μ Jb...
The Laplacian of the magnetic vector potential (A) is given by:
∇²A = ∇ · (∇A) - ∇ × (∇ × A)
where ∇ is the gradient operator and × is the cross product.
The Laplacian of A can be written in terms of the scalar and vector potentials as:
∇²A = ∇²(A_s) - ∇(∇ · A_v) + ∇ × (∇ × A_v)
where A_s is the scalar potential and A_v is the vector potential.
So, the Laplacian of the magnetic vector potential will be a combination of the Laplacians of the scalar and vector potentials, as well as terms involving the divergence and curl of the vector potential.
∇²A = ∇ · (∇A) - ∇ × (∇ × A)
where ∇ is the gradient operator and × is the cross product.
The Laplacian of A can be written in terms of the scalar and vector potentials as:
∇²A = ∇²(A_s) - ∇(∇ · A_v) + ∇ × (∇ × A_v)
where A_s is the scalar potential and A_v is the vector potential.
So, the Laplacian of the magnetic vector potential will be a combination of the Laplacians of the scalar and vector potentials, as well as terms involving the divergence and curl of the vector potential.
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The Laplacian of the magnetic vector potential will bea)–μ Jb)– μ Ic)–μ Bd)–μ HCorrect answer is option 'A'. Can you explain this answer?
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