The full-load copper-loss and iron loss of a transformer are 6400W and 5000W respectively. The copper-loss and ironloss at half load will be, respectivelya)3200W and 2500Wb)3200W and 5200Wc)1600W and 1250Wd)1600W and 5000WCorrect answer is option 'D'. Can you explain this answer?

Question

Answer

Given:
Full-load copper-loss = 6400 W
Full-load iron loss = 5000 W

To find:
Copper-loss and iron-loss at half-load

Solution:
At full-load, total losses = Copper-loss + Iron-loss
Total losses = 6400 + 5000 = 11400 W

At half-load, the copper-loss will reduce to half but the iron-loss will remain the same.

Copper-loss at half-load = 6400/2 = 3200 W

Total losses at half-load = Copper-loss at half-load + Iron-loss at half-load
Total losses at half-load = 3200 + Iron-loss at half-load

Total losses at half-load = Total losses at full-load/2 = 11400/2 = 5700 W

Iron-loss at half-load = Total losses at half-load - Copper-loss at half-load
Iron-loss at half-load = 5700 - 3200 = 2500 W

Therefore, the copper-loss and iron-loss at half-load are 3200 W and 2500 W respectively.

Hence, option D is the correct answer.

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