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Find the magnetic flux density of a finite length conductor of radius 12cm and current 3A in air( in 10-6 order)
- a)4
- b)5
- c)6
- d)7
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Find the magnetic flux density of a finite length conductor of radius ...
Answer: b
Explanation: The magnetic field intensity is given by H = I/2πr, where I = 3A and r = 0.12. The magnetic flux density in air B = μ H, where μ = 4π x 10-7.Thus B = 4π x 10-7 x 3/2π x 0.12 = 5x 10-6 units.
Explanation: The magnetic field intensity is given by H = I/2πr, where I = 3A and r = 0.12. The magnetic flux density in air B = μ H, where μ = 4π x 10-7.Thus B = 4π x 10-7 x 3/2π x 0.12 = 5x 10-6 units.
Most Upvoted Answer
Find the magnetic flux density of a finite length conductor of radius ...
To find the magnetic flux density of a finite length conductor, we can use Ampere's Law. Ampere's Law states that the magnetic field around a closed loop is proportional to the current passing through the loop.
The formula for magnetic flux density (B) due to a current-carrying conductor is given by:
B = (μ0 * I) / (2π * r)
Where:
B is the magnetic flux density
μ0 is the permeability of free space, which is a constant equal to 4π * 10^-7 Tm/A
I is the current in the conductor
r is the radius of the conductor
Given data:
Current (I) = 3A
Radius (r) = 12cm = 0.12m
Permeability of free space (μ0) = 4π * 10^-7 Tm/A
Calculating the magnetic flux density using the formula:
B = (μ0 * I) / (2π * r)
B = (4π * 10^-7 Tm/A * 3A) / (2π * 0.12m)
B = (4 * 3 * 10^-7 Tm) / (2 * 0.12m)
B = (12 * 10^-7 Tm) / (0.24m)
B = 50 * 10^-6 T
B = 5 * 10^-5 T
B = 5 * 10^-6 T (in 10^-6 order)
Therefore, the magnetic flux density is 5 * 10^-6 T, which corresponds to option B.
The formula for magnetic flux density (B) due to a current-carrying conductor is given by:
B = (μ0 * I) / (2π * r)
Where:
B is the magnetic flux density
μ0 is the permeability of free space, which is a constant equal to 4π * 10^-7 Tm/A
I is the current in the conductor
r is the radius of the conductor
Given data:
Current (I) = 3A
Radius (r) = 12cm = 0.12m
Permeability of free space (μ0) = 4π * 10^-7 Tm/A
Calculating the magnetic flux density using the formula:
B = (μ0 * I) / (2π * r)
B = (4π * 10^-7 Tm/A * 3A) / (2π * 0.12m)
B = (4 * 3 * 10^-7 Tm) / (2 * 0.12m)
B = (12 * 10^-7 Tm) / (0.24m)
B = 50 * 10^-6 T
B = 5 * 10^-5 T
B = 5 * 10^-6 T (in 10^-6 order)
Therefore, the magnetic flux density is 5 * 10^-6 T, which corresponds to option B.
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