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The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as ND The ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ = 1200).
- a)161.76:1
- b)33.1
- c)0.204:1
- d)0.0061:1
Correct answer is option 'A'. Can you explain this answer?
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To find the ratio of resistance taken along the longer ends to that taken along the shorter ends, we need to consider the resistivity of the semiconductor material, the dimensions of the specimen, and the concentration of donor atoms.
The resistance of a rectangular specimen can be calculated using the formula:
R = (ρ * L) / (A)
Where:
R = resistance
ρ = resistivity
L = length of the specimen
A = cross-sectional area of the specimen
In this case, we are given the dimensions of the specimen as 2.54 cm x 0.2 cm x 0.2 cm. Let's assume that the longer ends correspond to the 2.54 cm dimension, and the shorter ends correspond to the 0.2 cm dimension.
First, we need to calculate the cross-sectional area of the specimen:
A = (0.2 cm) * (0.2 cm) = 0.04 cm^2
Next, we need to calculate the resistance along the longer ends. The length of the specimen along the longer ends is 2.54 cm.
R_long = (ρ * 2.54 cm) / (0.04 cm^2)
Finally, we need to calculate the resistance along the shorter ends. The length of the specimen along the shorter ends is 0.2 cm.
R_short = (ρ * 0.2 cm) / (0.04 cm^2)
To find the ratio of the resistance along the longer ends to that along the shorter ends, we divide R_long by R_short:
Ratio = R_long / R_short
However, we are not given the value of the resistivity (ρ) of the semiconductor material. Without this information, we cannot calculate the ratio of the resistances.
The resistance of a rectangular specimen can be calculated using the formula:
R = (ρ * L) / (A)
Where:
R = resistance
ρ = resistivity
L = length of the specimen
A = cross-sectional area of the specimen
In this case, we are given the dimensions of the specimen as 2.54 cm x 0.2 cm x 0.2 cm. Let's assume that the longer ends correspond to the 2.54 cm dimension, and the shorter ends correspond to the 0.2 cm dimension.
First, we need to calculate the cross-sectional area of the specimen:
A = (0.2 cm) * (0.2 cm) = 0.04 cm^2
Next, we need to calculate the resistance along the longer ends. The length of the specimen along the longer ends is 2.54 cm.
R_long = (ρ * 2.54 cm) / (0.04 cm^2)
Finally, we need to calculate the resistance along the shorter ends. The length of the specimen along the shorter ends is 0.2 cm.
R_short = (ρ * 0.2 cm) / (0.04 cm^2)
To find the ratio of the resistance along the longer ends to that along the shorter ends, we divide R_long by R_short:
Ratio = R_long / R_short
However, we are not given the value of the resistivity (ρ) of the semiconductor material. Without this information, we cannot calculate the ratio of the resistances.
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The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer?
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The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer?.
The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The concentration of donor atoms is given for a semiconductor specimen (2.54cm x 0.2cm x 0.2cm). as NDThe ratio of resistance taken along the longer ends with that of taken along the shorter? (Given ND = 1016 cm3' μ= 1200).a)161.76:1b)33.1c)0.204:1d)0.0061:1Correct answer is option 'A'. Can you explain this answer?.
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