A heat pump uses 300 J of work to remove 400 J of heat from the low-temperature reservoir. How much heat is delivered to a higher temperature reservoir?a)500Jb)300Jc)700Jd)900JCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

Find the area of the triangle formed inside this graph using the given coordinates.(A=1/2*base*height).
and you will see the answer.
Thank you.

Answer

W = 300 J

Q_C= 400 J

Q_{H =}W + Q_C

Q_{H =}300 J + 400 J

Q_{H =} 700 J

Heat delivered to the higher temperature reservoir is 700 J.

Answer

To determine the amount of heat delivered to a higher temperature reservoir by a heat pump, we need to consider the principles of energy conservation and the efficiency of the heat pump.

Energy Conservation:
According to the principle of energy conservation, the total amount of energy in a closed system remains constant. In this case, the total energy is the sum of the work done by the heat pump and the heat removed from the low-temperature reservoir.

Efficiency of the Heat Pump:
The efficiency of a heat pump is defined as the ratio of the desired output (heat delivered to the higher temperature reservoir) to the required input (work done by the heat pump). Mathematically, efficiency is given by:

Efficiency = (Heat delivered to higher temperature reservoir) / (Work done by the heat pump)

Let's calculate the efficiency of the heat pump using the given values:

Efficiency = (400 J) / (300 J) = 4/3

This means that for every unit of work done by the heat pump, it delivers 4/3 units of heat to the higher temperature reservoir.

Calculating the Heat Delivered:
Now, to find the heat delivered to the higher temperature reservoir, we can use the efficiency calculated above and the work done by the heat pump.

Heat delivered = Efficiency * Work done by the heat pump

Heat delivered = (4/3) * (300 J) = 400 J

Therefore, the heat delivered to the higher temperature reservoir is 400 J.

Answer:
The correct option is c) 700 J.

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