Polarisation Vector in Air

Introduction:
The polarisation vector represents the alignment and magnitude of the electric dipole moments in a material when an external electric field is applied. It is given by the product of the susceptibility (χ) and the electric field (E).

Given:
Susceptibility (χ) = 5
Electric Field (E) = 12 units

Calculating the Polarisation Vector:
The polarisation vector (P) can be calculated using the formula: P = χ * E.

Given that χ = 5 and E = 12 units, we can substitute these values into the formula to find the polarisation vector:

P = 5 * 12 = 60 units

Therefore, the polarisation vector in air is 60 units.

Explanation:
The polarisation vector represents the dipole moment per unit volume in a material. When an external electric field is applied to a material, the electric dipoles in the material align themselves with the field. The degree of alignment depends on the susceptibility of the material.

In this case, the susceptibility of air is given as 5. A higher susceptibility value indicates a stronger alignment of the electric dipoles with the electric field. The electric field strength is given as 12 units.

To calculate the polarisation vector, we multiply the susceptibility by the electric field strength. In this case, the product of 5 and 12 gives a polarisation vector of 60 units.

Conclusion:
The polarisation vector in air, when the susceptibility is 5 and the electric field is 12 units, is 60 units. The polarisation vector represents the alignment and magnitude of electric dipole moments in the material.