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If cosA cos2A = 1 then the value of sin2A sin4A is?
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If cosA cos2A = 1 then the value of sin2A sin4A is?
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If cosA cos2A = 1 then the value of sin2A sin4A is?
Cosine Double Angle Formula:
The cosine double angle formula states that cos(2A) = 2cos^2(A) - 1.

Given:
cos(A) * cos(2A) = 1

Using the Cosine Double Angle Formula:
cos(2A) = 2cos^2(A) - 1

Substituting the given equation:
cos(A) * (2cos^2(A) - 1) = 1

Simplifying the equation:
2cos^3(A) - cos(A) = 1

Factoring out cos(A):
cos(A)(2cos^2(A) - 1) = 1

Dividing both sides by 2cos^2(A) - 1:
cos(A) = 1 / (2cos^2(A) - 1)

Using the Pythagorean Identity:
cos^2(A) + sin^2(A) = 1

Solving for sin^2(A):
sin^2(A) = 1 - cos^2(A)

Substituting into the equation:
cos(A) = 1 / (2(1 - sin^2(A)) - 1)

Simplifying the equation:
cos(A) = 1 / (2 - 2sin^2(A) - 1)
cos(A) = 1 / (1 - 2sin^2(A))

Cross-multiplying:
cos(A)(1 - 2sin^2(A)) = 1

Distributing:
cos(A) - 2sin^2(A)cos(A) = 1

Factoring out common term:
cos(A)(1 - 2sin^2(A)) = 1

Dividing both sides by cos(A):
1 - 2sin^2(A) = 1 / cos(A)

Using the Pythagorean Identity:
1 - 2sin^2(A) = sec(A)

Substituting into the equation:
sec(A) = 1 / cos(A)

Using the Reciprocal Identity:
1 / cos(A) = sec(A)

Substituting sec(A) back into the equation:
1 - 2sin^2(A) = sec(A)

Adding 2sin^2(A) to both sides:
1 = sec(A) + 2sin^2(A)

Substituting the given equation:
1 = cos(A) * cos(2A) + 2sin^2(A)

Using the Identity:
cos(2A) = 2cos^2(A) - 1

Substituting into the equation:
1 = cos(A) * (2cos^2(A) - 1) + 2sin^2(A)

Expanding the equation:
1 = 2cos^3(A) - cos(A) + 2sin^2(A)

Simplifying the equation:
2cos^3(A) + 2sin^
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If cosA cos2A = 1 then the value of sin2A sin4A is?
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