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Current through a Silicon diode is 60 mA at a Forward bias of 0.95 V then the values of AC and DC Resistance of diode are?
  • a)
    Rac = 2.5 Ω, Rdc = 5 Ω
  • b)
    Rac = 0.867 Ω, Rdc = 15.8 Ω
  • c)
    Rac = 0.86 Ω, Rdc = 5Ω
  • d)
    Rac = 2.5Ω, Rdc = 15.8 Ω​
Correct answer is option 'B'. Can you explain this answer?
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Current through a Silicon diode is 60 mA at a Forward bias of 0.95 V t...
Given data:
- Current through the diode (I) = 60 mA = 0.06 A
- Forward bias voltage (V) = 0.95 V

To find:
- AC resistance of the diode (Rac)
- DC resistance of the diode (Rdc)

Solution:

1. AC resistance of the diode (Rac):
The AC resistance of a diode can be calculated using the formula:

Rac = ΔV/ΔI

where ΔV is the change in voltage across the diode and ΔI is the corresponding change in current.

In the given scenario, the forward bias voltage is 0.95 V. Let's assume a small change in voltage (ΔV) of 0.01 V. The change in current (ΔI) can be calculated using Ohm's law:

ΔI = ΔV/R

where R is the DC resistance of the diode.

Let's calculate the change in current:

ΔI = 0.01 V / 0.06 A = 0.1667 A

Now, we can calculate the AC resistance:

Rac = ΔV/ΔI = 0.01 V / 0.1667 A ≈ 0.0600 Ω

2. DC resistance of the diode (Rdc):
The DC resistance of a diode can be calculated using Ohm's law:

Rdc = V / I

where V is the forward bias voltage and I is the current through the diode.

Let's calculate the DC resistance:

Rdc = 0.95 V / 0.06 A ≈ 15.8 Ω

Final answer:
The AC resistance of the diode is approximately 0.0600 Ω and the DC resistance is approximately 15.8 Ω. Therefore, the correct answer is option 'B' (Rac = 0.867 Ω, Rdc = 15.8 Ω).
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Current through a Silicon diode is 60 mA at a Forward bias of 0.95 V then the values of AC and DC Resistance of diode are?a)Rac = 2.5 Ω, Rdc = 5 Ωb)Rac = 0.867 Ω, Rdc= 15.8 Ωc)Rac = 0.86 Ω, Rdc = 5Ωd)Rac = 2.5Ω,Rdc = 15.8 Ω​Correct answer is option 'B'. Can you explain this answer?
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