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A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)
- a)21/2 sec
- b)23/2 sec
- c)21/4 sec
- d)23/4 sec
Correct answer is option 'D'. Can you explain this answer?
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A simple pendulum suspended from the ceiling of a stationary. Cart has...
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Time period of a simple pendulum is given by the formula:
T = 2π√(L/g)
where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
When the pendulum is in a stationary cart, the effective acceleration due to gravity is reduced by the acceleration of the cart. The net acceleration acting on the pendulum is the vector sum of the acceleration due to gravity and the acceleration of the cart.
Let's analyze the situation in a stationary frame of reference and a frame of reference moving with the cart.
In the stationary frame of reference:
- The acceleration due to gravity is g = 10 m/s^2.
- The length of the pendulum is not given.
In the frame of reference moving with the cart:
- The acceleration due to gravity is reduced by the acceleration of the cart, i.e., g' = g - a, where a is the acceleration of the cart.
- The length of the pendulum remains the same.
To find the time period of the pendulum in the moving cart, we can use the formula:
T' = 2π√(L/g')
where T' is the time period in the moving cart.
Now, let's substitute the given values into the equation:
T' = 2π√(L/(g - a))
Given:
T' = 2 seconds
g = 10 m/s^2
a = 10 m/s^2
Substituting the values:
2 = 2π√(L/(10 - 10))
Simplifying:
2 = 2π√(L/0)
Since the denominator is zero, it means that the time period is undefined in this case.
Therefore, the given information is contradictory, and it is not possible to determine the time period of the pendulum in the moving cart.
T = 2π√(L/g)
where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
When the pendulum is in a stationary cart, the effective acceleration due to gravity is reduced by the acceleration of the cart. The net acceleration acting on the pendulum is the vector sum of the acceleration due to gravity and the acceleration of the cart.
Let's analyze the situation in a stationary frame of reference and a frame of reference moving with the cart.
In the stationary frame of reference:
- The acceleration due to gravity is g = 10 m/s^2.
- The length of the pendulum is not given.
In the frame of reference moving with the cart:
- The acceleration due to gravity is reduced by the acceleration of the cart, i.e., g' = g - a, where a is the acceleration of the cart.
- The length of the pendulum remains the same.
To find the time period of the pendulum in the moving cart, we can use the formula:
T' = 2π√(L/g')
where T' is the time period in the moving cart.
Now, let's substitute the given values into the equation:
T' = 2π√(L/(g - a))
Given:
T' = 2 seconds
g = 10 m/s^2
a = 10 m/s^2
Substituting the values:
2 = 2π√(L/(10 - 10))
Simplifying:
2 = 2π√(L/0)
Since the denominator is zero, it means that the time period is undefined in this case.
Therefore, the given information is contradictory, and it is not possible to determine the time period of the pendulum in the moving cart.
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A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer?
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A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer?.
A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simple pendulum suspended from the ceiling of a stationary. Cart has a time period 2 seconds when the cart accelerates in the horizontal direction with an accelerates in the horizontal direction with an acceleration of 10 m/s2, the time period o f the pendulum is ( g = 10 m/see2)a)21/2 secb)23/2 secc)21/4 secd)23/4 secCorrect answer is option 'D'. Can you explain this answer?.
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