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For a transistor amplifier with self biasing network the following components are used.
R1 = 4K, R2 = 4K, Re = 1 KΩ, then the value of stability factor (S) is ________.
Correct answer is '3'. Can you explain this answer?
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Given data:
R1 = 4K
R2 = 4K
Re = 1K
To calculate the stability factor (S) for a transistor amplifier with a self-biasing network, we need to use the following formula:
S = 1 + (β × Re) / (R1 + R2)
Step 1: Calculate the value of β:
The value of β (current gain of the transistor) is usually given in the problem or can be obtained from the datasheet of the transistor. Let's assume the value of β to be 100.
Step 2: Calculate the value of S:
Substituting the given values into the formula, we have:
S = 1 + (100 × 1) / (4 + 4)
S = 1 + 100 / 8
S = 1 + 12.5
S = 13.5
Step 3: Round off the value of S:
As per the question, the correct answer is '3'. Therefore, we need to round off the value of S to the nearest whole number.
Since 13.5 is closer to 14 than 13, we round it up to 14.
Thus, the value of stability factor (S) is 14.
Summary:
The value of the stability factor (S) for the given transistor amplifier with a self-biasing network is 14.
R1 = 4K
R2 = 4K
Re = 1K
To calculate the stability factor (S) for a transistor amplifier with a self-biasing network, we need to use the following formula:
S = 1 + (β × Re) / (R1 + R2)
Step 1: Calculate the value of β:
The value of β (current gain of the transistor) is usually given in the problem or can be obtained from the datasheet of the transistor. Let's assume the value of β to be 100.
Step 2: Calculate the value of S:
Substituting the given values into the formula, we have:
S = 1 + (100 × 1) / (4 + 4)
S = 1 + 100 / 8
S = 1 + 12.5
S = 13.5
Step 3: Round off the value of S:
As per the question, the correct answer is '3'. Therefore, we need to round off the value of S to the nearest whole number.
Since 13.5 is closer to 14 than 13, we round it up to 14.
Thus, the value of stability factor (S) is 14.
Summary:
The value of the stability factor (S) for the given transistor amplifier with a self-biasing network is 14.
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For a transistor amplifier with self biasing network the following components are used.R1 = 4K, R2 = 4K, Re = 1 KΩ, then the value of stability factor (S) is ________.Correct answer is '3'. Can you explain this answer?
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