Pankaj walked at 5 km/h for certain part of the journey and then he to...
Let's assume that the distance traveled by Pankaj by auto is 'd' km.
To find the part of the journey traveled by auto, we need to find the ratio of the distance traveled by auto to the total distance.
Let's assume the total distance of the journey is 'x' km.
We know that Pankaj walked at a speed of 5 km/h for a certain part of the journey. So, the time taken for this part of the journey can be calculated as 't1 = (x - d) / 5' hours.
We also know that Pankaj took an auto for the remaining part of the journey and traveled at a speed of 25 km/h. So, the time taken for this part of the journey can be calculated as 't2 = d / 25' hours.
The total time taken for the entire journey is given as 10 hours. So, we can write the equation as:
t1 + t2 = 10
Substituting the values of t1 and t2, we get:
(x - d) / 5 + d / 25 = 10
Simplifying the equation, we get:
(5(x - d) + d) / 25 = 10
Multiplying both sides of the equation by 25, we get:
5(x - d) + d = 250
Expanding the equation, we get:
5x - 5d + d = 250
Simplifying the equation, we get:
5x - 4d = 250
Now, we also know that the average speed of the entire journey is 17 km/h. The average speed is calculated as the total distance divided by the total time taken. So, we can write another equation as:
x / 10 = 17
Multiplying both sides of the equation by 10, we get:
x = 170
Substituting the value of x in the equation 5x - 4d = 250, we get:
5(170) - 4d = 250
850 - 4d = 250
Subtracting 850 from both sides of the equation, we get:
-4d = -600
Dividing both sides of the equation by -4, we get:
d = 150
Therefore, Pankaj traveled 150 km by auto.
Hence, the correct answer is option C) 150 km.