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When an SCR full wave rectifier is connected across a sinusoidal voltage of 400 sin 314t, the RMS value of the current flowing through the device is 20 A. The power rating of the SCR is
- a)13.82 kW
- b)16.68kW
- c)12.47 kW
- d)11.87 kW
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
When an SCR full wave rectifier is connected across a sinusoidal volta...
As the supply voltage is 400 sin 314t
Vm = 400 V,
Peak invesre voltage (PIV)
RMS value of current = 20 A
Average value of current,
Vm = 400 V,
Peak invesre voltage (PIV)
RMS value of current = 20 A
Average value of current,
Most Upvoted Answer
When an SCR full wave rectifier is connected across a sinusoidal volta...
Calculation of Average Power
---------------------------
To find the power rating of the SCR full wave rectifier, we need to calculate the average power.
We know that the RMS value of the current is 20 A.
The formula for calculating the average power is P = Vrms * Irms * cos(φ).
Here, Vrms is the RMS value of the voltage, Irms is the RMS value of the current, and cos(φ) is the power factor.
In this case, the voltage waveform is sinusoidal. So, the RMS value of the voltage is given by Vrms = Vm / sqrt(2), where Vm is the peak voltage.
We have the equation for the voltage waveform as V = 400 sin 314t.
The peak voltage is Vm = 400 V.
Therefore, Vrms = 400 / sqrt(2) = 282.8 V.
The power factor for a full wave rectifier is 0.812.
Thus, the average power is P = 282.8 * 20 * 0.812 = 4585.6 W.
This is equal to 4.5856 kW.
Selection of Power Rating
-------------------------
The power rating of the SCR full wave rectifier should be higher than the calculated average power.
A suitable power rating would be 1.25 times the average power.
Therefore, the power rating should be 1.25 * 4.5856 kW = 5.732 kW.
Among the given options, option C, which is 12.47 kW, is the closest to the calculated power rating.
---------------------------
To find the power rating of the SCR full wave rectifier, we need to calculate the average power.
We know that the RMS value of the current is 20 A.
The formula for calculating the average power is P = Vrms * Irms * cos(φ).
Here, Vrms is the RMS value of the voltage, Irms is the RMS value of the current, and cos(φ) is the power factor.
In this case, the voltage waveform is sinusoidal. So, the RMS value of the voltage is given by Vrms = Vm / sqrt(2), where Vm is the peak voltage.
We have the equation for the voltage waveform as V = 400 sin 314t.
The peak voltage is Vm = 400 V.
Therefore, Vrms = 400 / sqrt(2) = 282.8 V.
The power factor for a full wave rectifier is 0.812.
Thus, the average power is P = 282.8 * 20 * 0.812 = 4585.6 W.
This is equal to 4.5856 kW.
Selection of Power Rating
-------------------------
The power rating of the SCR full wave rectifier should be higher than the calculated average power.
A suitable power rating would be 1.25 times the average power.
Therefore, the power rating should be 1.25 * 4.5856 kW = 5.732 kW.
Among the given options, option C, which is 12.47 kW, is the closest to the calculated power rating.
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When an SCR full wave rectifier is connected across a sinusoidal voltage of 400 sin 314t, the RMS value of the current flowing through the device is 20 A. The power rating of the SCR isa)13.82 kWb)16.68kWc)12.47 kWd)11.87 kWCorrect answer is option 'C'. Can you explain this answer?
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