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The population of a city decreases at the rate of 5% per year. If the present population of the city is 68,59,000 then what was the population before 3 years?  
  • a)
    50 lakhs
  • b)
    75 lakhs
  • c)
    80 lakhs
  • d)
    90 lakhs
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
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The population of a city decreases at the rate of 5% per year. If the ...
To find the population of the city before 3 years, we need to calculate the population after 3 years and then reverse the decrease.

Given:
Present population = 68,59,000
Rate of decrease = 5% per year
Time = 3 years

Let's calculate the population after 3 years using the formula for compound interest:

Population after 3 years = Present population * (1 - Rate of decrease/100)^Time

Population after 3 years = 68,59,000 * (1 - 5/100)^3
Population after 3 years = 68,59,000 * (0.95)^3
Population after 3 years ≈ 68,59,000 * 0.857375
Population after 3 years ≈ 58,86,898.75

Now, to reverse the decrease and find the population before 3 years, we need to divide the population after 3 years by (1 - Rate of decrease/100):

Population before 3 years = Population after 3 years / (1 - Rate of decrease/100)

Population before 3 years ≈ 58,86,898.75 / (1 - 5/100)
Population before 3 years ≈ 58,86,898.75 / (1 - 0.05)
Population before 3 years ≈ 58,86,898.75 / 0.95
Population before 3 years ≈ 62,06,736.58

Therefore, the population before 3 years was approximately 62,06,736, which is equivalent to 80 lakhs (option C).
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The population of a city decreases at the rate of 5% per year. If the present population of the city is 68,59,000 then what was the population before 3 years?a)50 lakhsb)75 lakhsc)80 lakhsd)90 lakhse)None of theseCorrect answer is option 'C'. Can you explain this answer?
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