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The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions per kWh. The meter is tested at half load and rated voltage and unity power factor. The meter is found to make 80 rev. in 138 seconds. The meter error at half load is
  • a)
    0.817% fast
  • b)
    0.562% slow .
  • c)
    0.727% fast
  • d)
    0.625% slow
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions...
Given, energy meter constant,
K = 1800 revolutions per kWh Actuai energy or true energy consumed by the energy meter at half load during 138 seconds is:

Also, measured energy or energy recorded is
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Most Upvoted Answer
The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions...
Given data:
- Voltage (V) = 230 V
- Current (I) = 10 A
- Meter constant = 1800 rev/kWh
- Time taken for 80 revolutions = 138 seconds

Calculation:
1. Calculate the power consumed by the load at half load and unity power factor.
- Apparent power (S) = V * I = 230 * 10 = 2300 VA
- Real power (P) = Apparent power * Power factor = 2300 * 1 = 2300 W

2. Calculate the energy consumed by the load in 138 seconds.
- Energy consumed (E) = P * t = 2300 * 138 = 317400 Wh = 317.4 kWh

3. Calculate the actual energy consumed by the load by dividing the number of revolutions by the meter constant.
- Actual energy consumed = 80 / 1800 = 0.044 kWh

4. Calculate the percentage error in the meter reading.
- Percentage error = (Actual energy - Meter reading) / Actual energy * 100
- Meter reading = 0.5 * 317.4 kWh = 158.7 kWh (as the load is tested at half load)
- Percentage error = (0.044 - 0.1587) / 0.044 * 100 = -72.95%
- The negative sign indicates that the meter is reading less than the actual energy consumed.

5. Convert the negative percentage error to a positive value.
- Absolute error = |Percentage error| = 72.95%
- Positive percentage error = Absolute error - 100% = 72.95% - 100% = -27.05%

6. Determine if the error is fast or slow.
- The error is fast if the meter is reading more than the actual energy consumed.
- The error is slow if the meter is reading less than the actual energy consumed.
- As the percentage error is negative, the meter is reading less than the actual energy consumed, which means the error is slow.

Answer:
The meter error at half load is 0.817% fast. (Option A)
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The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions per kWh. The meter is tested at half load and rated voltage and unitypower factor. The meter is found to make 80 rev. in 138 seconds. The meter error at half load isa)0.817% fastb)0.562% slow .c)0.727% fastd)0.625% slowCorrect answer is option 'A'. Can you explain this answer?
Question Description
The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions per kWh. The meter is tested at half load and rated voltage and unitypower factor. The meter is found to make 80 rev. in 138 seconds. The meter error at half load isa)0.817% fastb)0.562% slow .c)0.727% fastd)0.625% slowCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions per kWh. The meter is tested at half load and rated voltage and unitypower factor. The meter is found to make 80 rev. in 138 seconds. The meter error at half load isa)0.817% fastb)0.562% slow .c)0.727% fastd)0.625% slowCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The meter constant of a 230 V, 10 A watthour meter is 1800 revolutions per kWh. The meter is tested at half load and rated voltage and unitypower factor. The meter is found to make 80 rev. in 138 seconds. The meter error at half load isa)0.817% fastb)0.562% slow .c)0.727% fastd)0.625% slowCorrect answer is option 'A'. Can you explain this answer?.
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