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A single-phase half-bridge inverter has a resistive load of R = 3 Ω and the dc input voltage Vdc = 24 volts. The harmonic factor of the lowest order harmonic would be equal to
- a)33.33%
- b)25.0%
- c)66.67%
- d)50.0%
Correct answer is option 'A'. Can you explain this answer?
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A single-phase half-bridge inverter has a resistive load of R = 3 &Ome...
The lowest harmonic is third harmonic
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A single-phase half-bridge inverter has a resistive load of R = 3 &Ome...
In a single-phase half-bridge inverter with a resistive load of R = 3, the inverter will convert DC power to AC power by switching the polarity of the output voltage. The inverter consists of two switches, typically MOSFETs, connected in series with the load.
During the positive half-cycle of the AC waveform, the upper switch is turned on and the lower switch is turned off. This allows current to flow from the positive DC bus through the upper switch, through the load resistor, and back to the negative DC bus.
During the negative half-cycle of the AC waveform, the upper switch is turned off and the lower switch is turned on. This allows current to flow from the negative DC bus through the lower switch, through the load resistor in the opposite direction, and back to the positive DC bus.
By switching the polarity of the output voltage, the inverter creates an AC waveform across the load resistor with a frequency determined by the switching frequency of the switches. The magnitude of the output voltage will depend on the input DC voltage and the resistance of the load.
In the case of a resistive load of R = 3, the output current will be V/R, where V is the magnitude of the output voltage. The power dissipated in the load will be I^2 * R, where I is the output current.
During the positive half-cycle of the AC waveform, the upper switch is turned on and the lower switch is turned off. This allows current to flow from the positive DC bus through the upper switch, through the load resistor, and back to the negative DC bus.
During the negative half-cycle of the AC waveform, the upper switch is turned off and the lower switch is turned on. This allows current to flow from the negative DC bus through the lower switch, through the load resistor in the opposite direction, and back to the positive DC bus.
By switching the polarity of the output voltage, the inverter creates an AC waveform across the load resistor with a frequency determined by the switching frequency of the switches. The magnitude of the output voltage will depend on the input DC voltage and the resistance of the load.
In the case of a resistive load of R = 3, the output current will be V/R, where V is the magnitude of the output voltage. The power dissipated in the load will be I^2 * R, where I is the output current.
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A single-phase half-bridge inverter has a resistive load of R = 3 Ω and the dc input voltage Vdc = 24 volts. The harmonic factor of the lowest order harmonic would be equal toa)33.33%b)25.0%c)66.67%d)50.0%Correct answer is option 'A'. Can you explain this answer?
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