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The single-phase half-bridge inverter has a resistive load of 10Ω and the centre-tap dc input voltage is 96 V. The fundamental power consumed by the load is
- a)628.6 Watt
- b)525.0Watt'
- c)746.5 Watt
- d)824.4 Watt
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The single-phase half-bridge inverter has a resistive load of 10&Omega...
The single-phase half-bridge inverter is a type of inverter used to convert DC (direct current) power into AC (alternating current) power. It consists of two switches, usually MOSFETs, connected in series with a center-tapped transformer.
When the upper switch is turned on, the positive terminal of the DC source is connected to one end of the primary winding of the transformer, while the negative terminal is connected to the other end. This creates a current flow through the primary winding and induces a voltage across the secondary winding, which is then connected to the load.
When the lower switch is turned on, the polarity of the primary winding is reversed, resulting in a reversed polarity voltage across the secondary winding and load. By switching between the upper and lower switches at a high frequency, an AC voltage is generated across the load.
In this case, the resistive load of 10 ohms means that the load connected to the secondary winding of the transformer is purely resistive. This means that the load does not have any reactive components, such as inductance or capacitance, and only consumes power without storing or releasing it.
The output voltage and current waveform of the inverter will depend on the switching frequency, modulation technique, and control strategy used. The inverter can be controlled to provide different output voltages and frequencies by adjusting the duty cycle of the switching signals.
Overall, the single-phase half-bridge inverter with a resistive load of 10 ohms can be used in various applications where AC power is required, such as in household appliances, motor drives, and renewable energy systems.
When the upper switch is turned on, the positive terminal of the DC source is connected to one end of the primary winding of the transformer, while the negative terminal is connected to the other end. This creates a current flow through the primary winding and induces a voltage across the secondary winding, which is then connected to the load.
When the lower switch is turned on, the polarity of the primary winding is reversed, resulting in a reversed polarity voltage across the secondary winding and load. By switching between the upper and lower switches at a high frequency, an AC voltage is generated across the load.
In this case, the resistive load of 10 ohms means that the load connected to the secondary winding of the transformer is purely resistive. This means that the load does not have any reactive components, such as inductance or capacitance, and only consumes power without storing or releasing it.
The output voltage and current waveform of the inverter will depend on the switching frequency, modulation technique, and control strategy used. The inverter can be controlled to provide different output voltages and frequencies by adjusting the duty cycle of the switching signals.
Overall, the single-phase half-bridge inverter with a resistive load of 10 ohms can be used in various applications where AC power is required, such as in household appliances, motor drives, and renewable energy systems.
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The single-phase half-bridge inverter has a resistive load of 10&Omega...
The nth harmonic-component of output voltage is
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The single-phase half-bridge inverter has a resistive load of 10Ω and the centre-tap dc input voltage is 96 V. The fundamental power consumed by the load isa)628.6 Wattb)525.0Wattc)746.5 Wattd)824.4 WattCorrect answer is option 'C'. Can you explain this answer?
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The single-phase half-bridge inverter has a resistive load of 10Ω and the centre-tap dc input voltage is 96 V. The fundamental power consumed by the load isa)628.6 Wattb)525.0Wattc)746.5 Wattd)824.4 WattCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The single-phase half-bridge inverter has a resistive load of 10Ω and the centre-tap dc input voltage is 96 V. The fundamental power consumed by the load isa)628.6 Wattb)525.0Wattc)746.5 Wattd)824.4 WattCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The single-phase half-bridge inverter has a resistive load of 10Ω and the centre-tap dc input voltage is 96 V. The fundamental power consumed by the load isa)628.6 Wattb)525.0Wattc)746.5 Wattd)824.4 WattCorrect answer is option 'C'. Can you explain this answer?.
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