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The velocity of a bullet is reduced from 200m/s to 100m/s while travelling through a wooden block of thickness 10cm. The retardation, assuming it to be uniform, will be-?
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Calculation of Retardation of Bullet:

  • Initial velocity of the bullet, u = 200 m/s

  • Final velocity of the bullet, v = 100 m/s

  • Thickness of the wooden block, s = 10 cm = 0.1 m

  • Retardation of the bullet, a = ?



Explanation:
When a bullet passes through a wooden block, it experiences a force of resistance due to the wooden block. This force of resistance is known as retardation. The retardation is assumed to be uniform, which means that the force of resistance remains constant throughout the block.

According to the equation of motion, v^2 - u^2 = 2as
where,
v = final velocity
u = initial velocity
a = retardation
s = distance travelled

In this case, the bullet travels a distance of 0.1 m through the wooden block. Therefore, we can write:

v^2 - u^2 = 2as
(100)^2 - (200)^2 = 2 x a x 0.1
10000 - 40000 = 0.2a
a = -150000 m/s^2

The negative sign indicates that the retardation acts in the opposite direction to the motion of the bullet.

Conclusion:
The retardation of the bullet is calculated to be -150000 m/s^2. This means that the force of resistance experienced by the bullet is very high, which results in a significant reduction in its velocity as it passes through the wooden block.
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The velocity of a bullet is reduced from 200m/s to 100m/s while travelling through a wooden block of thickness 10cm. The retardation, assuming it to be uniform, will be-?
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