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There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box’s weight. The fourth box at 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four lightest boxes.
  • a)
    51.5 kg
  • b)
    75 kg
  • c)
    37.5 kg
  • d)
    112.5 kg
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
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Let's call the weight of the third box "x".

According to the problem, the weight of the second box is 20% higher than x, which means it is 1.2x.

And the weight of the third box is 25% higher than the first box, which means it is 1.25 times 200 kg, or 250 kg.

So now we know the weights of the first three boxes:

- First box: 200 kg
- Third box: x = 250 kg * 0.8 = 200 kg
- Second box: 1.2x = 1.2 * 200 kg = 240 kg

To find the total weight of the first three boxes, we just add them up:

200 kg + 200 kg + 240 kg = 640 kg

So the first three boxes weigh 640 kg.

We don't know the weights of the fourth and fifth boxes, so let's call them "y" and "z".

We know there are five boxes in total, so:

640 kg + y + z = total weight

We can't solve for the total weight without more information, but we can say that the weight of the fourth box plus the weight of the fifth box must be equal to the total weight minus 640 kg.
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There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box’s weight. The fourth box at 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four lightest boxes.a)51.5 kgb)75 kgc)37.5 kgd)112.5 kge)None of theseCorrect answer is option 'B'. Can you explain this answer?
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