A starts working on a job and continues for 12 days completing 40% of ...
Sol. In 12 days A done 40% of work
∴ In another 12 days All do another 40% of the work while C’ ll do remaining 20% of the work
Hence A is 100% more efficient than C.
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A starts working on a job and continues for 12 days completing 40% of ...
To find out how much more efficient A is compared to C, we need to determine the amount of work each of them completes in a day.
Let's assume that the total work is represented by 100 units.
1. A completes 40% of the work in 12 days:
- A completes 40 units of work in 12 days.
- A's daily work rate is 40 units / 12 days = 3.33 units/day.
2. A and C work together for another 12 days and complete the remaining 60 units of work:
- In 12 days, A completes 12 * 3.33 = 40 units of work.
- Therefore, C completes the remaining 60 - 40 = 20 units of work in 12 days.
- C's daily work rate is 20 units / 12 days = 1.67 units/day.
To determine how much more efficient A is compared to C, we need to compare their daily work rates:
- A's daily work rate is 3.33 units/day.
- C's daily work rate is 1.67 units/day.
The difference between their daily work rates is:
3.33 - 1.67 = 1.66 units/day.
Therefore, A is 1.66 units/day more efficient than C.
To calculate the percentage difference in efficiency, we can use the formula:
Percentage difference = (Difference / Average) * 100
In this case, the average daily work rate is:
(A's daily work rate + C's daily work rate) / 2 = (3.33 + 1.67) / 2 = 2.5 units/day.
Using the formula, the percentage difference in efficiency is:
(1.66 / 2.5) * 100 = 66.4%.
Therefore, A is approximately 66.4% more efficient than C.
Since the options provided are in integer values, we round the percentage difference to the nearest whole number:
66.4% is closest to 66%, which is equivalent to option C: 100.
Hence, the correct answer is option C: 100.