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In how many ways a committee of 5 can be chosen from 9 candidates?
  • a)
    178
  • b)
    126
  • c)
    292
  • d)
    268
  • e)
    None of these 
Correct answer is option 'B'. Can you explain this answer?
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In how many ways a committee of 5 can be chosen from 9 candidates?a)17...
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In how many ways a committee of 5 can be chosen from 9 candidates?a)17...
To determine the number of ways a committee of 5 can be chosen from 9 candidates, we can use the concept of combinations.

Combinations:
Combinations are a way to calculate the number of ways to choose objects from a larger set without considering the order in which they are chosen. The formula for combinations is given by:

C(n, r) = n! / (r!(n-r)!)

Where C(n, r) represents the number of combinations of n objects taken r at a time, and ! denotes the factorial function.

Explanation:
In this case, we have 9 candidates from which we need to choose a committee of 5. Therefore, we can calculate the number of ways to choose the committee using the combination formula as follows:

C(9, 5) = 9! / (5!(9-5)!)

Simplifying the equation:

C(9, 5) = (9 * 8 * 7 * 6 * 5!) / (5! * 4 * 3 * 2 * 1)

The 5! terms in the numerator and denominator cancel out:

C(9, 5) = (9 * 8 * 7 * 6) / (4 * 3 * 2 * 1)

C(9, 5) = 9 * 2 * 7

C(9, 5) = 126

Therefore, there are 126 ways to choose a committee of 5 from 9 candidates.

Answer:
The correct answer is option B) 126.
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In how many ways a committee of 5 can be chosen from 9 candidates?a)178b)126c)292d)268e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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