In how many ways a committee of 5 can be chosen from 9 candidates?a)17...
To determine the number of ways a committee of 5 can be chosen from 9 candidates, we can use the concept of combinations.
Combinations:
Combinations are a way to calculate the number of ways to choose objects from a larger set without considering the order in which they are chosen. The formula for combinations is given by:
C(n, r) = n! / (r!(n-r)!)
Where C(n, r) represents the number of combinations of n objects taken r at a time, and ! denotes the factorial function.
Explanation:
In this case, we have 9 candidates from which we need to choose a committee of 5. Therefore, we can calculate the number of ways to choose the committee using the combination formula as follows:
C(9, 5) = 9! / (5!(9-5)!)
Simplifying the equation:
C(9, 5) = (9 * 8 * 7 * 6 * 5!) / (5! * 4 * 3 * 2 * 1)
The 5! terms in the numerator and denominator cancel out:
C(9, 5) = (9 * 8 * 7 * 6) / (4 * 3 * 2 * 1)
C(9, 5) = 9 * 2 * 7
C(9, 5) = 126
Therefore, there are 126 ways to choose a committee of 5 from 9 candidates.
Answer:
The correct answer is option B) 126.