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The strength of current in 1 Henry inductor changes at a rate of 1 A/sec. The magnitude of energy stored in the inductor after 3 sec is
  • a)
    2 Joules
  • b)
    3.8 Joules
  • c)
    4.5 Joules
  • d)
    2.2 Joules
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The strength of current in 1 Henry inductor changes at a rate of 1 A/s...
∴ Current in the inductor after 3 sec is 
1= 3 A
Hence, energy stored after 3 sec.
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Most Upvoted Answer
The strength of current in 1 Henry inductor changes at a rate of 1 A/s...
Calculation of Energy Stored in an Inductor:

The energy stored in an inductor can be calculated using the formula:

E = 1/2 * L * I^2

where E is the energy stored in Joules, L is the inductance in Henry and I is the current in Amperes.

Given data:

Inductance, L = 1 Henry

Rate of change of current, dI/dt = 1 A/sec

Time, t = 3 sec

Calculation:

From the given data, the rate of change of current is constant, therefore, we can find the current at any time using the formula:

I = dI/dt * t

I = 1 A/sec * 3 sec = 3 A

Now, using the formula for energy stored in an inductor:

E = 1/2 * L * I^2

E = 1/2 * 1 Henry * (3 A)^2

E = 4.5 Joules

Therefore, the magnitude of energy stored in the inductor after 3 seconds is 4.5 Joules, which is option 'C'.
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The strength of current in 1 Henry inductor changes at a rate of 1 A/sec. The magnitude of energy stored in the inductor after 3 sec isa)2 Joulesb)3.8 Joulesc)4.5 Joulesd)2.2 JoulesCorrect answer is option 'C'. Can you explain this answer?
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