Class 10 Exam > Class 10 Questions > In case of a real and inverted image the magn...
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In case of a real and inverted image the magnification of a mirror is
- a)positive and large
- b)negative
- c)positive and small
- d)negative and large
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In case of a real and inverted image the magnification of a mirror isa...
Magnification is negative for a real and inverted image formed by a mirror.
Most Upvoted Answer
In case of a real and inverted image the magnification of a mirror isa...
When the image is real and inverted the size of the image is negative while size of object is positive. So the magnification of the image is negative.Therefore option(b) is correct
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Community Answer
In case of a real and inverted image the magnification of a mirror isa...
Explanation:
The magnification of a mirror is the ratio of the height of the image to the height of the object. It can be positive or negative depending on the type of image formed.
Real and Inverted Image:
When an object is placed in front of a mirror, the image formed can be either real or virtual, and either upright or inverted. In the case of a real and inverted image, the image is formed on the opposite side of the mirror and is inverted (upside down).
Magnification:
The magnification of a real and inverted image is always negative. This means that the height of the image is negative as compared to the height of the object. The magnification formula is given as:
Magnification (m) = Height of image (hi) / Height of object (ho)
If hi is negative (i.e. inverted image), then m will be negative.
Options:
Option (a) Positive and Large: This cannot be the correct answer as the magnification is always negative for a real and inverted image.
Option (b) Negative: This is the correct answer as the magnification is always negative for a real and inverted image.
Option (c) Positive and Small: This cannot be the correct answer as the magnification is always negative for a real and inverted image.
Option (d) Negative and Large: The magnification can be negative, but it cannot be large or small. The magnitude of the magnification depends on the distance of the object from the mirror and the focal length of the mirror.
The magnification of a mirror is the ratio of the height of the image to the height of the object. It can be positive or negative depending on the type of image formed.
Real and Inverted Image:
When an object is placed in front of a mirror, the image formed can be either real or virtual, and either upright or inverted. In the case of a real and inverted image, the image is formed on the opposite side of the mirror and is inverted (upside down).
Magnification:
The magnification of a real and inverted image is always negative. This means that the height of the image is negative as compared to the height of the object. The magnification formula is given as:
Magnification (m) = Height of image (hi) / Height of object (ho)
If hi is negative (i.e. inverted image), then m will be negative.
Options:
Option (a) Positive and Large: This cannot be the correct answer as the magnification is always negative for a real and inverted image.
Option (b) Negative: This is the correct answer as the magnification is always negative for a real and inverted image.
Option (c) Positive and Small: This cannot be the correct answer as the magnification is always negative for a real and inverted image.
Option (d) Negative and Large: The magnification can be negative, but it cannot be large or small. The magnitude of the magnification depends on the distance of the object from the mirror and the focal length of the mirror.
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In case of a real and inverted image the magnification of a mirror isa)positive and largeb)negativec)positive and smalld)negative and largeCorrect answer is option 'B'. Can you explain this answer?
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