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Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?
- a)30 cm in front of mirror
- b)15 cm in front of mirror
- c)Between 15 cm and 30 cm in front of mirror
- d)Less than 15 cm in front of mirror
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Rays from sun converge at a point 15 cm in front of a concave mirror. ...
As light rays from sun (u = ∞) converge at a point 15 cm in front of a concave mirror, hence focal length of concave mirror f = - 15 cm.
To form an image of exactly same size as that of an object, the object should be placed at the centre of curvature (u = R = 2f) of mirror. Hence, the object should be placed at 30 cm in front of mirror.
To form an image of exactly same size as that of an object, the object should be placed at the centre of curvature (u = R = 2f) of mirror. Hence, the object should be placed at 30 cm in front of mirror.
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Rays from sun converge at a point 15 cm in front of a concave mirror. ...
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Rays from sun converge at a point 15 cm in front of a concave mirror. ...
Solution:
Given, Rays from sun converge at a point 15 cm in front of a concave mirror.
To find, the position of the object to get the image size equal to the object size.
Let's consider the below diagram for better understanding.
From the given information,
- The image is formed at the focus (F) of the concave mirror.
- The object distance (u) is to be found.
Using the mirror formula,
1/f = 1/v - 1/u
As the image is formed at the focus, v = f.
1/f = 1/f - 1/u
1/f = 1/f - 1/u
1/f = (u-f)/uf
uf = f(u-f)
u = f(u-f)/f
u = u-f
2f = u
Therefore, the object distance (u) should be twice the focal length (f) to get the image size equal to the object size.
Given that the image is formed at a distance of 15 cm from the mirror, which is the focal length (f) of the mirror.
Therefore, u = 2f = 2 x 15 cm = 30 cm.
Hence, the correct option is (a) 30 cm in front of the mirror.
Given, Rays from sun converge at a point 15 cm in front of a concave mirror.
To find, the position of the object to get the image size equal to the object size.
Let's consider the below diagram for better understanding.
From the given information,
- The image is formed at the focus (F) of the concave mirror.
- The object distance (u) is to be found.
Using the mirror formula,
1/f = 1/v - 1/u
As the image is formed at the focus, v = f.
1/f = 1/f - 1/u
1/f = 1/f - 1/u
1/f = (u-f)/uf
uf = f(u-f)
u = f(u-f)/f
u = u-f
2f = u
Therefore, the object distance (u) should be twice the focal length (f) to get the image size equal to the object size.
Given that the image is formed at a distance of 15 cm from the mirror, which is the focal length (f) of the mirror.
Therefore, u = 2f = 2 x 15 cm = 30 cm.
Hence, the correct option is (a) 30 cm in front of the mirror.
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Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer?
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Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer?.
Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?a)30 cm in front of mirrorb)15 cm in front of mirrorc)Between 15 cm and 30 cm in front of mirrord)Less than 15 cm in front of mirrorCorrect answer is option 'A'. Can you explain this answer?.
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