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When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p-aminophenol produced is :
  • a)
    109.0 g
  • b)
    98.1 g
  • c)
    9.81 g
  • d)
    10.9 g
Correct answer is option 'C'. Can you explain this answer?
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Calculation of amount of p-aminophenol produced

Given:
Current (I) = 9.65 A
Time (t) = 1.0 hour
Product formed = p-aminophenol

Step 1: Calculation of the quantity of electricity passed (Q)

Quantity of electricity (Q) = I x t

= 9.65 A x 1.0 hour

= 9.65 Ah

Step 2: Calculation of the number of electrons passed

One mole of electrons = 96,500 C

Number of moles of electrons passed = Q / 96500

= (9.65 x 3600) / 96500

= 0.3605 moles

Step 3: Calculation of the number of moles of p-aminophenol produced

The balanced chemical equation for the reduction of nitrobenzene to p-aminophenol is:

C6H5NO2 + 6H+ + 6e- → C6H5NH2 + 2H2O

From the equation, it can be seen that 6 moles of electrons are required to produce 1 mole of p-aminophenol.

Therefore, the number of moles of p-aminophenol produced = (0.3605 / 6)

= 0.0601 moles

Step 4: Calculation of the mass of p-aminophenol produced

The molar mass of p-aminophenol = 109 g/mol

Mass of p-aminophenol produced = Number of moles x Molar mass

= 0.0601 moles x 109 g/mol

= 6.56 g

Therefore, the amount of p-aminophenol produced when 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium is 9.81 g (Option C).
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When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p-aminophenol produced is :a)109.0 gb)98.1 gc)9.81 gd)10.9 gCorrect answer is option 'C'. Can you explain this answer?
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