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Infinite number of bodies, each of mass 2 kg are situated on x-axis at distances 1m, 2m, 4m, 8m, … ,
respectively, from the origin. The resulting gravitational potential due to this system at the origin will be -
  • a)
    -G
  • b)
    -8/3G
  • c)
    -4/3 G
  • d)
    -4G
Correct answer is option 'D'. Can you explain this answer?
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Infinite number of bodies, each of mass 2 kg are situated on x-axis at...
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Infinite number of bodies, each of mass 2 kg are situated on x-axis at...
And so on from the origin. Find the gravitational potential at a point P on the x-axis, where P is at a distance of 3 meters from the origin.

Solution:

Let G be the universal gravitational constant, and let M be the mass of each body. Then the gravitational potential at point P due to all the bodies can be found by summing the contributions from each body:

V = -GM(1/1 + 1/2 + 1/4 + 1/8 + ...)

This is an infinite series, but we can simplify it using the formula for a geometric series:

1 + r + r^2 + r^3 + ... = 1/(1-r)

where r is the common ratio. In this case, the common ratio is 1/2, so we have:

1/1 + 1/2 + 1/4 + 1/8 + ... = 1/(1-1/2) = 2

Therefore, the gravitational potential at point P is given by:

V = -GM(2) = -2GM

Substituting the numerical values, we get:

V = -(6.67 x 10^-11 N m^2/kg^2)(2 kg)(2) = -2.22 x 10^-10 J/kg

Note that the gravitational potential is negative, indicating that work must be done to bring a mass from infinity to point P against the gravitational force.
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Infinite number of bodies, each of mass 2 kg are situated on x-axis at distances 1m, 2m, 4m, 8m, … ,respectively, from the origin. The resulting gravitational potential due to this system at the origin will be -a)-Gb)-8/3Gc)-4/3 Gd)-4GCorrect answer is option 'D'. Can you explain this answer?
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