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In the given figure, AD/BD = AE/EC and ∠ADE = 70°, ∠BAC = 50°, then angle ∠BCA =
  • a)
    70°
  • b)
    50°
  • c)
    80°
  • d)
    60°
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In the given figure, AD/BD = AE/EC and ∠ADE = 70°,∠BAC = 5...
Explanation:
By converse of Thale’s theorem DE II BC  
∠ADE = ∠ABC = 70 degree  
Given ∠BAC = 50 degree

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Most Upvoted Answer
In the given figure, AD/BD = AE/EC and ∠ADE = 70°,∠BAC = 5...
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Community Answer
In the given figure, AD/BD = AE/EC and ∠ADE = 70°,∠BAC = 5...
By using angle sum property we find third angle
AED=180-(70+50)=60and DEllBC so, by córesponding angle we get the value of BCA=60.
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In the given figure, AD/BD = AE/EC and ∠ADE = 70°,∠BAC = 50°, then angle ∠BCA =a)70°b)50°c)80°d)60°Correct answer is option 'D'. Can you explain this answer?
Question Description
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