Two trains each of length 100 m moving parallel towards each other at speed 72 km /h and 36 km/h respectively. In how much time will they cross each other ?

Question

Answer

total distance=200 (distance of first train head to the second train head)speed is 30 m/s (speed of both train added)t=d/t200/30 = 6.67sec

Answer

6.33 sec

Answer

ya  ans is 6.67 actually I have got ans w.r.t to one train so sry for tha

Answer

3.3 sec

Answer

6.67 sec

Answer

6.67 secs

Answer

ans is 6.67 bt kaise

Answer

Given:
- Length of each train = 100 m
- Speed of first train = 72 km/h
- Speed of second train = 36 km/h

To find:
- Time taken by the two trains to cross each other

Formula:
- Relative speed = Sum of the speeds of the two trains

Calculation:
Given that the speed of the first train is 72 km/h and the speed of the second train is 36 km/h.

The relative speed of the two trains can be calculated by summing up their speeds:
Relative speed = 72 km/h + 36 km/h = 108 km/h

We need to convert this relative speed from km/h to m/s, since the length of the trains is given in meters.
To convert km/h to m/s, we divide the speed in km/h by 3.6:
Relative speed = 108 km/h ÷ 3.6 = 30 m/s

Now, let's calculate the time taken by the two trains to cross each other using the formula:
Time = Distance ÷ Speed

The distance to be covered by the two trains to cross each other is the sum of their lengths:
Distance = Length of first train + Length of second train
Distance = 100 m + 100 m = 200 m

Now, we can substitute the values into the formula to find the time:
Time = 200 m ÷ 30 m/s = 6.67 seconds

Answer:
The two trains will cross each other in approximately 6.67 seconds.

Answer

total distance=200 (distance of the train ends)speed is 30 m/s (speed of both train added)t=d/t200/30 = 6.67sec

Answer

10

Answer

3.3 sec

Answer

6.67sec

Answer

According to me it's 15 second
For 1st train=D=100m,Speed=20m/s
Time =D/S
100/20=5m/s
For 2 nd train =D=100m,Speed = 10m/s
Time =D/S
100/10= 10m/s
And as we know when the train moves in opposite direction we add
so
10+5=15 sec

Answer

total distance=200 (distance of the train ends)speed is 30 m/s (speed of both train added)t=d/t200/30 = 6.33sec

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