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4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may be
- a)SO₂
- b)CO
- c)O₂
- d)CO₂
Correct answer is option 'D'. Can you explain this answer?
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4.4 g of an unknown gas occupies 2.24 litres of volume at standard tem...
so CO2 is correct answer
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4.4 g of an unknown gas occupies 2.24 litres of volume at standard tem...
Given:
Mass of gas = 4.4 g
Volume of gas = 2.24 L
Gas at STP
We can use the ideal gas law to determine the number of moles of the gas present:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP, the pressure is 1 atm and the temperature is 273 K. Therefore, we can write:
n = PV/RT = (1 atm)(2.24 L)/(0.0821 L·atm/mol·K)(273 K) = 0.092 mol
Next, we can use the molar mass of each gas to determine which gas has a mass of 4.4 g and a mole number of 0.092 mol:
a) SO₂: Molar mass = 64.06 g/mol. Mass of 0.092 mol = 5.89 g, which is greater than the given mass of 4.4 g. Therefore, SO₂ cannot be the gas.
b) CO: Molar mass = 28.01 g/mol. Mass of 0.092 mol = 2.57 g, which is less than the given mass of 4.4 g. Therefore, CO cannot be the gas.
c) O₂: Molar mass = 32.00 g/mol. Mass of 0.092 mol = 2.94 g, which is less than the given mass of 4.4 g. Therefore, O₂ cannot be the gas.
d) CO₂: Molar mass = 44.01 g/mol. Mass of 0.092 mol = 4.04 g, which is very close to the given mass of 4.4 g. Therefore, CO₂ is the gas.
Hence, the correct answer is option 'D' (CO₂).
Mass of gas = 4.4 g
Volume of gas = 2.24 L
Gas at STP
We can use the ideal gas law to determine the number of moles of the gas present:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP, the pressure is 1 atm and the temperature is 273 K. Therefore, we can write:
n = PV/RT = (1 atm)(2.24 L)/(0.0821 L·atm/mol·K)(273 K) = 0.092 mol
Next, we can use the molar mass of each gas to determine which gas has a mass of 4.4 g and a mole number of 0.092 mol:
a) SO₂: Molar mass = 64.06 g/mol. Mass of 0.092 mol = 5.89 g, which is greater than the given mass of 4.4 g. Therefore, SO₂ cannot be the gas.
b) CO: Molar mass = 28.01 g/mol. Mass of 0.092 mol = 2.57 g, which is less than the given mass of 4.4 g. Therefore, CO cannot be the gas.
c) O₂: Molar mass = 32.00 g/mol. Mass of 0.092 mol = 2.94 g, which is less than the given mass of 4.4 g. Therefore, O₂ cannot be the gas.
d) CO₂: Molar mass = 44.01 g/mol. Mass of 0.092 mol = 4.04 g, which is very close to the given mass of 4.4 g. Therefore, CO₂ is the gas.
Hence, the correct answer is option 'D' (CO₂).
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4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer?.
4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4.4 g of an unknown gas occupies 2.24 litres of volume at standard temperature and pressure. The gas may bea)SOb)COc)Od)COCorrect answer is option 'D'. Can you explain this answer?.
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