Specific conductance of 0.01 M KCl solution is x ohm1 cm1. When conductivity cell is filled with 0.01 M KCl the conductance observed is y ohm1. When the same cell is filled with 0.01 M H2SO4, the observed conductance was Z ohm1 cm1. Hence specific conductance of 0.01 M H2SO4 is:a)xzb)z/xyc)xz/yd)xy/zCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

To find the specific conductance of 0.01 M H2SO4 solution, we can use the concept of specific conductance and conductance.

Given:
Specific conductance of 0.01 M KCl solution = x ohm^-1 cm^-1
Conductance observed with 0.01 M KCl in the conductivity cell = y ohm^-1
Conductance observed with 0.01 M H2SO4 in the same conductivity cell = z ohm^-1 cm^-1

The specific conductance of a solution is defined as the conductance of a solution in a cell of unit dimensions (1 cm^2 cross-sectional area and 1 cm distance between the electrodes). It is represented by the symbol κ (kappa) and is given by the equation:

κ = G × l

Where G is the conductance of the solution and l is the distance between the electrodes.

Let's calculate the specific conductance of the 0.01 M KCl solution using the given data:

κ(KCl) = G(KCl) × l

κ(KCl) = y ohm^-1 × 1 cm

κ(KCl) = y ohm^-1 cm^-1

So, the specific conductance of the 0.01 M KCl solution is y ohm^-1 cm^-1.

Now, let's calculate the specific conductance of the 0.01 M H2SO4 solution using the given data:

κ(H2SO4) = G(H2SO4) × l

κ(H2SO4) = z ohm^-1 × 1 cm

κ(H2SO4) = z ohm^-1 cm^-1

So, the specific conductance of the 0.01 M H2SO4 solution is z ohm^-1 cm^-1.

To find the specific conductance of the 0.01 M H2SO4 solution in terms of x, y, and z, we can use the concept of ratios.

Specific conductance of 0.01 M H2SO4 solution = κ(H2SO4) = z ohm^-1 cm^-1

According to the given options, we need to find z in terms of x, y, and z. Let's evaluate the options:

a) xz
b) z/xy
c) xz/y
d) xy/z

Comparing the given options with the obtained result for the specific conductance of the 0.01 M H2SO4 solution (z ohm^-1 cm^-1), we find that option c) xz/y is the correct answer.

Therefore, the specific conductance of the 0.01 M H2SO4 solution is xz/y ohm^-1 cm^-1.

Answer

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