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Find the en by a train 150 m long running at a speed of 63 kmph to cross  another train of length 100 m long running at ph in the same direction
    Correct answer is '75'. Can you explain this answer?
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    Find the en by a train 150 m long running at a speed of 63 kmph to cro...
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    Find the en by a train 150 m long running at a speed of 63 kmph to cro...
    Approach to solve the problem:
    To find the time taken by the train to cross another train, we need to calculate the relative speed between the two trains.

    Given data:
    - Length of first train (L1) = 150 m
    - Speed of first train (S1) = 63 kmph
    - Length of second train (L2) = 100 m
    - Speed of second train (S2) = ? (to be found)

    Formula:
    Relative speed = (Speed of first train - Speed of second train)

    Calculations:
    - Speed of first train = 63 kmph = 63 * (5/18) m/s = 35/2 m/s
    - Let the speed of the second train be S m/s
    - Relative speed = (35/2 - S) m/s

    Time taken to cross the second train:
    Time = Distance / Relative speed
    Time = (L1 + L2) / (35/2 - S)

    Given data:
    - L1 = 150 m
    - L2 = 100 m

    Substitute the values:
    Time = (150 + 100) / (35/2 - S)
    Time = 250 / (35/2 - S)
    Time = 500 / (35 - 2S)

    Given that the trains are moving in the same direction:
    - Speed of first train (S1) = 35/2 m/s
    - Speed of second train (S2) = S m/s

    Relative speed formula:
    Relative speed = 35/2 - S

    Given that the relative speed is equal to the speed of the second train:
    35/2 - S = S
    35 = 2S + S
    35 = 3S
    S = 35/3
    S = 11.67 m/s

    Time taken to cross the second train:
    Time = 500 / (35 - 2(11.67))
    Time = 500 / (35 - 23.34)
    Time = 500 / 11.66
    Time ≈ 42.88 seconds

    Answer:
    Therefore, the time taken by the train to cross another train is approximately 43 seconds.
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    Find the en by a train 150 m long running at a speed of 63 kmph to cross another train of length 100 m long running at ph in the same directionCorrect answer is '75'. Can you explain this answer?
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