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Find the en by a train 150 m long running at a speed of 63 kmph to cross another train of length 100 m long running at ph in the same direction
Correct answer is '75'. Can you explain this answer?
Most Upvoted Answer
Find the en by a train 150 m long running at a speed of 63 kmph to cro...
Approach to solve the problem:
To find the time taken by the train to cross another train, we need to calculate the relative speed between the two trains.
Given data:
- Length of first train (L1) = 150 m
- Speed of first train (S1) = 63 kmph
- Length of second train (L2) = 100 m
- Speed of second train (S2) = ? (to be found)
Formula:
Relative speed = (Speed of first train - Speed of second train)
Calculations:
- Speed of first train = 63 kmph = 63 * (5/18) m/s = 35/2 m/s
- Let the speed of the second train be S m/s
- Relative speed = (35/2 - S) m/s
Time taken to cross the second train:
Time = Distance / Relative speed
Time = (L1 + L2) / (35/2 - S)
Given data:
- L1 = 150 m
- L2 = 100 m
Substitute the values:
Time = (150 + 100) / (35/2 - S)
Time = 250 / (35/2 - S)
Time = 500 / (35 - 2S)
Given that the trains are moving in the same direction:
- Speed of first train (S1) = 35/2 m/s
- Speed of second train (S2) = S m/s
Relative speed formula:
Relative speed = 35/2 - S
Given that the relative speed is equal to the speed of the second train:
35/2 - S = S
35 = 2S + S
35 = 3S
S = 35/3
S = 11.67 m/s
Time taken to cross the second train:
Time = 500 / (35 - 2(11.67))
Time = 500 / (35 - 23.34)
Time = 500 / 11.66
Time ≈ 42.88 seconds
Answer:
Therefore, the time taken by the train to cross another train is approximately 43 seconds.
To find the time taken by the train to cross another train, we need to calculate the relative speed between the two trains.
Given data:
- Length of first train (L1) = 150 m
- Speed of first train (S1) = 63 kmph
- Length of second train (L2) = 100 m
- Speed of second train (S2) = ? (to be found)
Formula:
Relative speed = (Speed of first train - Speed of second train)
Calculations:
- Speed of first train = 63 kmph = 63 * (5/18) m/s = 35/2 m/s
- Let the speed of the second train be S m/s
- Relative speed = (35/2 - S) m/s
Time taken to cross the second train:
Time = Distance / Relative speed
Time = (L1 + L2) / (35/2 - S)
Given data:
- L1 = 150 m
- L2 = 100 m
Substitute the values:
Time = (150 + 100) / (35/2 - S)
Time = 250 / (35/2 - S)
Time = 500 / (35 - 2S)
Given that the trains are moving in the same direction:
- Speed of first train (S1) = 35/2 m/s
- Speed of second train (S2) = S m/s
Relative speed formula:
Relative speed = 35/2 - S
Given that the relative speed is equal to the speed of the second train:
35/2 - S = S
35 = 2S + S
35 = 3S
S = 35/3
S = 11.67 m/s
Time taken to cross the second train:
Time = 500 / (35 - 2(11.67))
Time = 500 / (35 - 23.34)
Time = 500 / 11.66
Time ≈ 42.88 seconds
Answer:
Therefore, the time taken by the train to cross another train is approximately 43 seconds.
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