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Area of a triangle :
If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:
Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]
Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).
- a)29 units
- b)35.9 sq.units
- c)39 sq.units
- d)39.5 sq.units
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertic...
Here, x1 = 9, x2 = 3, x3 = -2 and y1 = -5, y2 = 7, y3 = 4
= 1/2 [9(7-4) + 3(4+5) + (-2)(-5-7)]
= 1/2 [9(3) + 3(9) - 2(-12)]
= 1/2 [27 + 27 + 24]
= 1/2 [78]
= 39 sq.units
= 1/2 [9(7-4) + 3(4+5) + (-2)(-5-7)]
= 1/2 [9(3) + 3(9) - 2(-12)]
= 1/2 [27 + 27 + 24]
= 1/2 [78]
= 39 sq.units
Most Upvoted Answer
Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertic...
Area=1/2[9(3)+3(9)+(-2)(-12)]
=1/2[27+27+24]
=1/2[78]
=39 sq.units
Area=39 sq.units
=1/2[27+27+24]
=1/2[78]
=39 sq.units
Area=39 sq.units
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Community Answer
Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertic...
Triangle, then the area of the triangle can be calculated using the following formula:
Area = 1/2 * |(x1*(y2-y3) + x2*(y3-y1) + x3*(y1-y2))|
where | | represents the absolute value.
This formula is based on the concept of the determinant of a matrix, where the coordinates of the three vertices are represented as a matrix and the determinant of that matrix is calculated to get the area of the triangle.
Area = 1/2 * |(x1*(y2-y3) + x2*(y3-y1) + x3*(y1-y2))|
where | | represents the absolute value.
This formula is based on the concept of the determinant of a matrix, where the coordinates of the three vertices are represented as a matrix and the determinant of that matrix is calculated to get the area of the triangle.
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Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer?
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Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer?.
Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer?.
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Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Area of a triangle :If A(x1,y1), B(x2,y2 and C(x3, y3) be three vertices of a ΔABC, then its area is given by:Δ = 1/2 [x1(y2 - y3 + x2(y3 - y1) + x3(y1 - y2)]Find the area of ΔABC whose vertices are A(9, -5), B(3, 7) and (-2, 4).a)29 unitsb)35.9 sq.unitsc)39 sq.unitsd)39.5 sq.unitsCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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