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Eight dipoles of charges of magnitude are placed inside a cube. The total electric flux coming out of the cube will be

  • a)
    zero

  • b)
    q/ε₀

  • c)
    8q/ε₀

  • d)
    16q/ε₀

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Eight dipoles of charges of magnitude are placed inside a cube. The t...
Explanation:

 

  • Electric Flux: The electric flux through a closed surface is given by the total electric field passing through that surface.

  • Gauss's Law: According to Gauss's Law, the total electric flux through a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of free space (ε₀).

  • Given Situation: In this case, there are eight dipoles of charges inside a cube. Since dipoles consist of equal and opposite charges separated by a distance, the total charge enclosed by the cube is zero.

  • Total Electric Flux: Therefore, the total electric flux coming out of the cube is zero as there is no net charge enclosed.

  • Therefore, the correct answer is A: zero.


  •  
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Most Upvoted Answer
Eight dipoles of charges of magnitude are placed inside a cube. The t...
Because Gauss law says total enclosed charge/€0= Flux... but here each dipole having same positive and negative charges thus forming net charge zero. thus net enclosed charge will be zero inside the cube thus no net flux
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Community Answer
Eight dipoles of charges of magnitude are placed inside a cube. The t...
Net change will be Zero..inside cube
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