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The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V . This tube is connected with another tube of same but half the radius in series. Then the rate of steady volume flow through them is (pressure across the combination is P)
- a)V/16
- b)V/17
- c)16V/17
- d)17V/16
Correct answer is option 'B'. Can you explain this answer?
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The rate of steady volume flow of water through a capillary tube of le...
Given:
Rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V.
To find:
The rate of steady volume flow through the combined tube.
Solution:
Let the first capillary tube have radius r and the second tube have radius r/2.
Volume flow rate through the first tube is given by Poiseuille's law as:
V = (πr^4P)/(8ηl)
where η is the viscosity of water.
The volume flow rate through the second tube can be calculated using the same formula with radius r/2:
V' = (π(r/2)^4P)/(8ηl)
Simplifying this equation we get:
V' = (V/16)
The pressure difference across the combination of the tubes is still P as they are in series. Therefore, using the same formula, the total volume flow rate is:
V_total = (π(r^4 + (r/2)^4)P)/(8ηl)
Simplifying this equation we get:
V_total = (17V/16)
Therefore, the rate of steady volume flow through the combined tube is V/17.
Answer:
The correct option is B) V/17.
Rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V.
To find:
The rate of steady volume flow through the combined tube.
Solution:
Let the first capillary tube have radius r and the second tube have radius r/2.
Volume flow rate through the first tube is given by Poiseuille's law as:
V = (πr^4P)/(8ηl)
where η is the viscosity of water.
The volume flow rate through the second tube can be calculated using the same formula with radius r/2:
V' = (π(r/2)^4P)/(8ηl)
Simplifying this equation we get:
V' = (V/16)
The pressure difference across the combination of the tubes is still P as they are in series. Therefore, using the same formula, the total volume flow rate is:
V_total = (π(r^4 + (r/2)^4)P)/(8ηl)
Simplifying this equation we get:
V_total = (17V/16)
Therefore, the rate of steady volume flow through the combined tube is V/17.
Answer:
The correct option is B) V/17.
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The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V . This tube is connected with another tube of same but half the radius in series. Then the rate of steady volume flow through them is (pressure across the combination is P)a) V/16 b) V/17 c) 16V/17 d) 17V/16 Correct answer is option 'B'. Can you explain this answer?
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The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V . This tube is connected with another tube of same but half the radius in series. Then the rate of steady volume flow through them is (pressure across the combination is P)a) V/16 b) V/17 c) 16V/17 d) 17V/16 Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V . This tube is connected with another tube of same but half the radius in series. Then the rate of steady volume flow through them is (pressure across the combination is P)a) V/16 b) V/17 c) 16V/17 d) 17V/16 Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V . This tube is connected with another tube of same but half the radius in series. Then the rate of steady volume flow through them is (pressure across the combination is P)a) V/16 b) V/17 c) 16V/17 d) 17V/16 Correct answer is option 'B'. Can you explain this answer?.
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