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Lights from two different sources A and B have wavelength 0.3 micron and 0.7 micron respectively. Which one of the two light carry more energy per photon ?
- a)light sources A
- b)Both the lights have same energy
- c)None of these
- d)Light source B
Correct answer is option 'A'. Can you explain this answer?
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Explanation:
To determine which light carries more energy per photon, we need to use the equation:
E = hc/λ
where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the light.
Calculations:
Let's calculate the energy of the photons from sources A and B using the given wavelengths.
For source A:
E(A) = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (0.3 x 10^-6 m)
E(A) = 6.626 x 3 / 0.3 x 10^-6 J
E(A) = 19.878 x 10^-6 J
E(A) = 1.9878 x 10^-5 J
For source B:
E(B) = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (0.7 x 10^-6 m)
E(B) = 6.626 x 3 / 0.7 x 10^-6 J
E(B) = 18.978 x 10^-6 J
E(B) = 1.8978 x 10^-5 J
Comparison:
Comparing the energy of the photons from sources A and B, we can see that:
E(A) = 1.9878 x 10^-5 J
E(B) = 1.8978 x 10^-5 J
Since E(A) is greater than E(B), it means that each photon from source A carries more energy compared to each photon from source B.
Conclusion:
Therefore, the light from source A carries more energy per photon compared to the light from source B.
To determine which light carries more energy per photon, we need to use the equation:
E = hc/λ
where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the light.
Calculations:
Let's calculate the energy of the photons from sources A and B using the given wavelengths.
For source A:
E(A) = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (0.3 x 10^-6 m)
E(A) = 6.626 x 3 / 0.3 x 10^-6 J
E(A) = 19.878 x 10^-6 J
E(A) = 1.9878 x 10^-5 J
For source B:
E(B) = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (0.7 x 10^-6 m)
E(B) = 6.626 x 3 / 0.7 x 10^-6 J
E(B) = 18.978 x 10^-6 J
E(B) = 1.8978 x 10^-5 J
Comparison:
Comparing the energy of the photons from sources A and B, we can see that:
E(A) = 1.9878 x 10^-5 J
E(B) = 1.8978 x 10^-5 J
Since E(A) is greater than E(B), it means that each photon from source A carries more energy compared to each photon from source B.
Conclusion:
Therefore, the light from source A carries more energy per photon compared to the light from source B.
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Lights from two different sources A and B have wavelength 0.3 micron and 0.7 micron respectively. Which one of the two light carry more energy per photon ?a)light sources Ab)Both the lights have same energyc)None of thesed)Light source BCorrect answer is option 'A'. Can you explain this answer?
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