B1,B2and B3 are the three identical bulb connected as shown in the figure. Ammeter À1,A2 and A3 are connected shown in the figure.when all the bulb glow,then the current of 3 A is recorded by ammeterA. What happened to the reading of A1 ,A2 when the bulb are Vw gets fused?

Question

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I think your question is incomplete because you did not upload the required figure for this question.So, upload the required figure.

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Ok but where is the Figure

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Dear...but where is ur question's figure...

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Where is figure?

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Actually I am not seeing you required image

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Https://www.toppr.com/ask/question/what-happens-to-the-reading-of-a1-a2-a3-and-a-when-the-bulb-b2/

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Where is the figure???

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Hey listen where Is the required figure for this question

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Explanation:

When all three bulbs B1, B2, and B3 are glowing, the current of 3A is recorded by ammeter A. However, if one of the bulbs, let's say B2, gets fused, it will affect the current and the readings of ammeters A1 and A2.

Reasoning:

When all three bulbs are connected in parallel, the current passing through each bulb is the same. Therefore, each bulb receives 1A of current when all three bulbs are glowing. This means that ammeter A records a total current of 3A.

Now, if bulb B2 gets fused, it will create an open circuit in that branch. This will result in an increase in resistance in the circuit, as the resistance of the fused bulb becomes infinite.

Effect on Ammeter A1:

When bulb B2 gets fused, the resistance in the branch containing B2 increases. As a result, the total resistance of the circuit increases. According to Ohm's Law (V = IR), if the resistance increases, the current decreases if the voltage remains constant.

Since the voltage across the circuit remains constant, the decrease in current will be distributed across the remaining bulbs B1 and B3. Therefore, the current passing through B1 and B3 will decrease, and consequently, the current recorded by ammeter A1 will also decrease.

Effect on Ammeter A2:

Similarly, when bulb B2 gets fused, the resistance in the branch containing B2 increases, resulting in an increase in the total resistance of the circuit. This increase in resistance will cause a decrease in the current passing through the circuit.

Since ammeter A2 is connected in series with bulb B2, it measures the current passing through B2. Therefore, when B2 gets fused, the current passing through B2 becomes zero, and ammeter A2 will record a current of zero.

Summary:

- When one of the bulbs, B2, gets fused, it creates an open circuit in that branch, increasing the resistance of the circuit.
- The increase in resistance causes a decrease in the total current passing through the circuit.
- As a result, the current passing through bulbs B1 and B3 also decreases.
- Ammeter A1, which measures the current passing through B1, will record a decreased current.
- Ammeter A2, which measures the current passing through B2, will record zero current since B2 is fused.

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