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6 students of nursery class are playing a game. They are standing in a circle and have to pass a ball among themselves. How many such passes are possible? 
  • a)
    32760 
  • b)
    15625 
  • c)
    30 
  • d)
    36 
  • e)
    46656
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
6 students of nursery class are playing a game. They are standing in a...
Solution:
To solve this problem, we can use the formula for the number of ways to arrange n objects in a circle, which is (n-1)!.

Step 1:
We need to find the number of ways to arrange 6 objects (the students) in a circle. Using the formula, we get (6-1)! = 5! = 120.

Step 2:
Now that we know there are 120 ways to arrange the students in a circle, we need to count the number of ways they can pass the ball among themselves. Each student can pass the ball to any of the other 5 students, so there are 5 choices for the first pass. After the first pass, there are 5 students left who can receive the ball, so there are 5 choices for the second pass. This continues until all 6 students have passed the ball.

Step 3:
To find the total number of passes, we need to multiply the number of choices for each pass. So the total number of passes is 5 x 5 x 5 x 5 x 5 x 5 = 5^6 = 15625.

Therefore, the correct answer is option B (15625).
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Community Answer
6 students of nursery class are playing a game. They are standing in a...
As there are 6 students and each can pass ball to 5 students. so on multiplying 5 six times we get 15625
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