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In an ideal transformer, the voltage and the current in the primary are 200 volt and 2amp respectively. If the voltage in the secondary is 2000 volt. Then value of current (in Amp) in the secondary will be :
Correct answer is '0.2'. Can you explain this answer?
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Verified Answer
In an ideal transformer, the voltage and the current in the primary ar...
Voltage in primary vp = 200volt
Current in primary ip = 2amp
Voltage in secondary vs = 200volt
The relation for the current in the secondary is
The correct answer is: 0.2
The correct answer is: 0.2
Most Upvoted Answer
In an ideal transformer, the voltage and the current in the primary ar...
Voltage in primary vp = 200volt
Current in primary ip = 2amp
Voltage in secondary vs = 200volt
The relation for the current in the secondary is
The correct answer is: 0.2
The correct answer is: 0.2
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Community Answer
In an ideal transformer, the voltage and the current in the primary ar...
Given:
Primary voltage (V1) = 200 V
Primary current (I1) = 2 A
Secondary voltage (V2) = 2000 V
To find:
Secondary current (I2)
Explanation:
The ideal transformer is based on the principle of electromagnetic induction. According to this principle, a changing magnetic field induces an electromotive force (EMF) in a coil of wire. In a transformer, this EMF is induced in the secondary coil due to the changing magnetic field created by the primary coil.
Step 1: Understand the transformer equation
The transformer equation relates the primary and secondary voltages and currents:
\(\frac{V_1}{V_2} = \frac{I_1}{I_2}\)
This equation states that the ratio of the primary voltage to the secondary voltage is equal to the ratio of the primary current to the secondary current.
Step 2: Apply the transformer equation
Substituting the given values into the transformer equation:
\(\frac{200}{2000} = \frac{2}{I_2}\)
Step 3: Solve for I2
To find I2, we can rearrange the equation:
\(\frac{200}{2000} = \frac{2}{I_2}\)
Cross-multiplying:
\(200 \times I_2 = 2000 \times 2\)
Simplifying:
\(200 \times I_2 = 4000\)
Dividing both sides by 200:
\(I_2 = \frac{4000}{200}\)
\(I_2 = 20\)
Step 4: Convert the current to Amperes
Since the answer is expected in Amperes, we need to convert the current from 20 A to 0.2 A.
\(I_2 = 0.2\) A
Therefore, the value of the current in the secondary is 0.2 A.
Primary voltage (V1) = 200 V
Primary current (I1) = 2 A
Secondary voltage (V2) = 2000 V
To find:
Secondary current (I2)
Explanation:
The ideal transformer is based on the principle of electromagnetic induction. According to this principle, a changing magnetic field induces an electromotive force (EMF) in a coil of wire. In a transformer, this EMF is induced in the secondary coil due to the changing magnetic field created by the primary coil.
Step 1: Understand the transformer equation
The transformer equation relates the primary and secondary voltages and currents:
\(\frac{V_1}{V_2} = \frac{I_1}{I_2}\)
This equation states that the ratio of the primary voltage to the secondary voltage is equal to the ratio of the primary current to the secondary current.
Step 2: Apply the transformer equation
Substituting the given values into the transformer equation:
\(\frac{200}{2000} = \frac{2}{I_2}\)
Step 3: Solve for I2
To find I2, we can rearrange the equation:
\(\frac{200}{2000} = \frac{2}{I_2}\)
Cross-multiplying:
\(200 \times I_2 = 2000 \times 2\)
Simplifying:
\(200 \times I_2 = 4000\)
Dividing both sides by 200:
\(I_2 = \frac{4000}{200}\)
\(I_2 = 20\)
Step 4: Convert the current to Amperes
Since the answer is expected in Amperes, we need to convert the current from 20 A to 0.2 A.
\(I_2 = 0.2\) A
Therefore, the value of the current in the secondary is 0.2 A.
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In an ideal transformer, the voltage and the current in the primary are200voltand2amprespectively. If the voltage in the secondary is2000volt.Then value of current (inAmp) in the secondary will be :Correct answer is '0.2'. Can you explain this answer?
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