In an ideal transformer, the voltage and the current in the primary are200voltand2amprespectively. If the voltage in the secondary is2000volt.Then value of current (inAmp) in the secondary will be :Correct answer is '0.2'. Can you explain this answer?

Question

Answer

Voltage in primary v_p = 200volt

Current in primary i_p = 2amp

Voltage in secondary v_s = 200volt

The relation for the current in the secondary is

The correct answer is: 0.2

Answer

Given:
Primary voltage (V1) = 200 V
Primary current (I1) = 2 A
Secondary voltage (V2) = 2000 V

To find:
Secondary current (I2)

Explanation:

The ideal transformer is based on the principle of electromagnetic induction. According to this principle, a changing magnetic field induces an electromotive force (EMF) in a coil of wire. In a transformer, this EMF is induced in the secondary coil due to the changing magnetic field created by the primary coil.

Step 1: Understand the transformer equation
The transformer equation relates the primary and secondary voltages and currents:

$\frac{V_1}{V_2} = \frac{I_1}{I_2}$

This equation states that the ratio of the primary voltage to the secondary voltage is equal to the ratio of the primary current to the secondary current.

Step 2: Apply the transformer equation
Substituting the given values into the transformer equation:

$\frac{200}{2000} = \frac{2}{I_2}$

Step 3: Solve for I2
To find I2, we can rearrange the equation:

$\frac{200}{2000} = \frac{2}{I_2}$

Cross-multiplying:

$200 \times I_2 = 2000 \times 2$

Simplifying:

$200 \times I_2 = 4000$

Dividing both sides by 200:

$I_2 = \frac{4000}{200}$

$I_2 = 20$

Step 4: Convert the current to Amperes
Since the answer is expected in Amperes, we need to convert the current from 20 A to 0.2 A.

$I_2 = 0.2$ A

Therefore, the value of the current in the secondary is 0.2 A.

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