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A 50 Hz A.C. current of peak value 1A flows through the primary coil of a transformer. If the mutual inductance between primary and secondary is 1.5 H. the mean value of the induced voltage (in V) is ________ .
    Correct answer is '300'. Can you explain this answer?
    Verified Answer
    A 50 Hz A.C. current of peak value 1A flows through the primary coil o...
    Frequency of A.C. n = 50 Hz
    time period T 
    Time in which current changes from peak
    value (ii) to zero (ii
    i.e. 
    then Δi- change in current 
    = ii — ii = 0 — 1 = - 1 A .
    ∴ mean induced e.m.f.

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    Most Upvoted Answer
    A 50 Hz A.C. current of peak value 1A flows through the primary coil o...
    Given data:
    - Frequency of AC current (f) = 50 Hz
    - Peak value of AC current (Ip) = 1 A
    - Mutual inductance (M) = 1.5 H

    Mean value of the induced voltage:
    The mean value of the induced voltage can be found using the formula:

    Vm = 4*f*M*Ip

    Calculating the mean value of the induced voltage:
    Substituting the given values into the formula:

    Vm = 4*50*1.5*1

    Vm = 4*75

    Vm = 300 V

    Therefore, the mean value of the induced voltage is 300 V.
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    A 50 Hz A.C. current of peak value 1A flows through the primary coil of a transformer. If the mutual inductance between primary and secondary is 1.5 H. the mean value of the induced voltage (in V) is ________ .Correct answer is '300'. Can you explain this answer?
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