The secondary coil of an ideal step down transformer is delivering500W...
P = VI
For an ideal transformer (100% efficient)
The correct answer is:
2.5A
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The secondary coil of an ideal step down transformer is delivering500W...
Given:
- Power delivered by the secondary coil, P = 500 W
- Current flowing through the secondary coil, I = 12.5 A
- Turns ratio, Np/Ns = 5:1
To find:
Current flowing through the primary coil
Solution:
Step 1: Calculate the voltage across the secondary coil using the power formula:
P = V * I
where P is the power, V is the voltage, and I is the current.
Given that P = 500 W and I = 12.5 A, we can rearrange the formula to find V:
V = P / I = 500 W / 12.5 A = 40 V
So, the voltage across the secondary coil is 40 V.
Step 2: Use the turns ratio to calculate the voltage across the primary coil.
The turns ratio is given as Np/Ns = 5:1.
Since the voltage is directly proportional to the number of turns, we can write the equation as:
Vp/Vs = Np/Ns
Substituting the known values, we have:
Vp/40 V = 5/1
Cross-multiplying, we get:
Vp = 40 V * (5/1) = 200 V
So, the voltage across the primary coil is 200 V.
Step 3: Calculate the current flowing through the primary coil using the power formula:
P = V * I
where P is the power, V is the voltage, and I is the current.
Given that P = 500 W and V = 200 V, we can rearrange the formula to find I:
I = P / V = 500 W / 200 V = 2.5 A
Therefore, the current flowing through the primary coil is 2.5 A.
Conclusion:
The current flowing in the primary coil of the transformer is 2.5 A. Hence, the correct answer is option B.
The secondary coil of an ideal step down transformer is delivering500W...
P = VI
For an ideal transformer (100% efficient)
The correct answer is:
2.5A