The sum of 4th term and 8th term of an AP is 24 and the sum of the 6th...
Solution:
Given:
- Sum of 4th and 8th term of an AP is 24
- Sum of 6th and 10th term is 44
To Find:
- First three terms of AP
Explanation:
Let us assume the first term of the AP is 'a' and the common difference is 'd'. Then the fourth term will be 'a+3d', the sixth term will be 'a+5d', the eighth term will be 'a+7d', and the tenth term will be 'a+9d'.
Equation 1:
- Sum of 4th and 8th term of an AP is 24
(a+3d) + (a+7d) = 24
2a + 10d = 24
a + 5d = 12
Equation 2:
- Sum of 6th and 10th term of an AP is 44
(a+5d) + (a+9d) = 44
2a + 14d = 44
a + 7d = 22
Solving the Equations:
- Subtract Equation 1 from Equation 2
(a+7d) - (a+5d) = 22 - 12
2d = 10
d = 5
- Substitute the value of 'd' in Equation 1 or 2
a + 5(5) = 12 OR a + 7(5) = 22
a = -13 OR a = -3
Answer:
Therefore, the first three terms of the AP can be:
- -13, -8, -3 (when a = -13)
- -3, 2, 7 (when a = -3)
Conclusion:
The first three terms of the AP can be -13, -8, -3 or -3, 2, 7 depending on the value of 'a'.